C#实现矩阵转置的方法

/// <summary>/// 求一个矩阵的转置矩阵/// </summary>/// <param name="matrix">矩阵</param>/// <returns>转置矩阵</returns>private static double[][] MatrixTranspose(double[][] matrix){ //合法性检查 if (!isMatrix(matrix)) {  throw new Exception("matrix 不是一个矩阵"); } //矩阵中没有元素的情况 if (matrix.Length == 0) {  return new double[][] { }; } double[][] result = new double[matrix[0].Length][]; for (int i = 0; i < result.Length; i++) {  result[i] = new double[matrix.Length]; } //新矩阵生成规则： b[i,j]=a[j,i] for (int i = 0; i < result.Length; i++) {  for (int j = 0; j < result[0].Length; j++)  {   result[i][j] = matrix[j][i];  } } return result;}

/// <summary>/// 判断一个二维数组是否为矩阵/// </summary>/// <param name="matrix">二维数组</param>/// <returns>true:是矩阵 false:不是矩阵</returns>private static bool isMatrix(double[][] matrix){ //空矩阵是矩阵 if (matrix.Length < 1) return true; //不同行列数如果不相等，则不是矩阵 int count = matrix[0].Length; for (int i = 1; i < matrix.Length; i++) {  if (matrix[i].Length != count)  {   return false;  } } //各行列数相等，则是矩阵 return true;}/// <summary>/// 打印矩阵/// </summary>/// <param name="matrix">待打印矩阵</param>private static void PrintMatrix(double[][] matrix){ for (int i = 0; i < matrix.Length; i++) {  for (int j = 0; j < matrix[i].Length; j++)  {   Console.Write(matrix[i][j] + "/t");   //注意不能写为：Console.Write(matrix[i][j] + '/t');  }  Console.WriteLine(); }}

static void Main(string[] args){ double[][] matrix = new double[][]  {  new double[] { 1, 2, 3, 4 },  new double[] { 4, 5, 6, 7 },  new double[] { 7, 8, 9, 10} }; //打印矩阵 PrintMatrix(matrix); Console.WriteLine(); //打印转置后矩阵 PrintMatrix(MatrixTranspose(matrix)); Console.WriteLine(); Console.ReadLine();}