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Struts2框架实现简单的用户登入

2019-11-15 00:36:50
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Struts2框架实现简单的用户登入

Struts框架汲取了Struts的优点,以WebWork为核心,拦截器,可变和可重用的标签。

第一步:加载Struts2 类库:

第二步:配置web.xml

<?xml version="1.0" encoding="UTF-8"?><web-app version="2.5"     xmlns="http://java.sun.com/xml/ns/javaee"     xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"     xsi:schemaLocation="http://java.sun.com/xml/ns/javaee     http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">  <welcome-file-list>    <welcome-file>index.jsp</welcome-file>  </welcome-file-list>    <!-- 配置Struts2过滤器 :拦截请求 -->  <filter>      <filter-name>Struts2</filter-name>      <filter-class>org.apache.struts2.dispatcher.ng.filter.StrutsPRepareAndExecuteFilter</filter-class>  </filter>  <filter-mapping>      <filter-name>Struts2</filter-name>      <url-pattern>/*</url-pattern><!--'/*' 过滤所有请求 -->  </filter-mapping>  </web-app>

第三步:开发视图层页面(提交表单页)

<%@ page language="java" import="java.util.*" pageEncoding="UTF-8"%><%String path = request.getContextPath();String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";%><!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"><html>  <head>    <base href="<%=basePath%>">        <title>Struts2Demo</title>      </head>    <body>    <h1>HelloWorld Struts2</h1>    <hr>    <form action="LonginAction" method="post">        <p>用户名:<input type="text" name="username" /></p>        <p>密   码:<input type="passWord" name="password" /></p>        <p><input type="submit" /></p>    </form>  </body></html>
四:三层架构:
package dao;/** * 用户操作接口 * @author Administrator * */public interface UserDao {        public String login(String username,String password);}
package biz;/** * 用户业务接口 * @author Administrator * */public interface UserBiz {        public String login(String username,String password);}
package biz.impl;import biz.UserBiz;import dao.UserDao;import dao.UserDaoImpl;public class UserBizImpl implements UserBiz {        //创建dao层对象    UserDao userdao = new UserDaoImpl();        /**     * 调用dao层方法     */        public String login(String username, String password) {                return userdao.login(username, password);    }}
package dao;public class UserDaoImpl implements UserDao {    public String login(String username, String password) {        String str = "";        if(username.equals("msit") && password.equals("123456")){            str = "success";        }else{            str = "error";        }                // TODO Auto-generated method stub        return str;    }}

第五步:开发控制层Action

package Action;import java.util.Map;import javax.servlet.http.HttpServletRequest;import javax.servlet.http.HttpServletResponse;import javax.servlet.http.Httpsession;import org.apache.struts2.ServletActionContext;import biz.UserBiz;import biz.impl.UserBizImpl;import com.opensymphony.xwork2.ActionContext;import com.opensymphony.xwork2.ActionSupport;/** * 登录控制器 * @author Administrator * */public class LoginAction extends ActionSupport{        /*值栈:页面可以直接获取*/    String username;//form表单name;进行封装    String password;//form表单name;进行封装        //创建Biz层对象    UserBiz userbiz = new UserBizImpl();                    /* (non-Javadoc)     * @see com.opensymphony.xwork2.ActionSupport#execute()     */    @Override    public String execute() throws Exception {        // TODO Auto-generated method stub        System.out.println(username+"==="+password);                /*解耦(降低依赖)方式;基于Map集合*/        ActionContext ac = ActionContext.getContext();        /*得到request*/        Map request = (Map) ac.get("request");        //request.put("username", username);        /*得到session*/        Map session = ac.getSession();        /*得到application*/        Map application = ac.getApplication();        //===================================================        /*耦合(依懒性)方式*/        HttpServletRequest request2 = ServletActionContext.getRequest();        HttpServletResponse response = ServletActionContext.getResponse();        HttpSession session2 = request2.getSession();                //request2.setAttribute("username", username);                /**         * struts默认提供了五个状态字符串         */        return userbiz.login(username, password);    }            /**     * @return the username     */    public String getUsername() {        return username;    }    /**     * @param username the username to set     */    public void setUsername(String username) {        this.username = username;    }    /**     * @return the password     */    public String getPassword() {        return password;    }    /**     * @param password the password to set     */    public void setPassword(String password) {        this.password = password;    }}

第六步:配置struts.xml(核心文件);可以参照struts-default.xml

<?xml version="1.0" encoding="UTF-8"?><!DOCTYPE struts PUBLIC    "-//Apache Software Foundation//DTD Struts Configuration 2.3//EN"    "http://struts.apache.org/dtds/struts-2.3.dtd">    <struts>        <!-- 配置包信息 -->        <package name="default" namespace="/" extends="struts-default">            <!-- 配置Action:关联Action JavaBean -->            <action name="LonginAction" class="Action.LoginAction">                <!-- 指定返回的视图 ;默认使用转发-->                <result name="success">success.jsp</result>                <result name="error">error.jsp</result>            </action>        </package>    </struts>

第七步:处理完逻辑之后返回相应的字符串success、error跳转到相应的页面

<%@ page language="java" import="java.util.*" pageEncoding="UTF-8"%><%String path = request.getContextPath();String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";%><!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"><html>  <head>    <base href="<%=basePath%>">        <title>My JSP 'success.jsp' starting page</title>        <meta http-equiv="pragma" content="no-cache">    <meta http-equiv="cache-control" content="no-cache">    <meta http-equiv="expires" content="0">        <meta http-equiv="keywords" content="keyword1,keyword2,keyword3">    <meta http-equiv="description" content="This is my page">    <!--    <link rel="stylesheet" type="text/CSS" href="styles.css">    -->  </head>    <body>   ${username } 登陆成功!!! <br>  </body></html>
<%@ page language="java" import="java.util.*" pageEncoding="UTF-8"%><%String path = request.getContextPath();String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";%><!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"><html>  <head>    <base href="<%=basePath%>">        <title>My JSP 'error.jsp' starting page</title>        <meta http-equiv="pragma" content="no-cache">    <meta http-equiv="cache-control" content="no-cache">    <meta http-equiv="expires" content="0">        <meta http-equiv="keywords" content="keyword1,keyword2,keyword3">    <meta http-equiv="description" content="This is my page">    <!--    <link rel="stylesheet" type="text/css" href="styles.css">    -->  </head>    <body>    登录失败 <br>  </body></html>

注意:

配置struts2    1、加入类库(jar包)—从应用实例当中拷贝    2、在web.xml中配置过滤器        <!-- 配置Struts2过滤器  -->          <filter>            <filter-name>Struts2</filter-name>            <filter-class>org.apache.struts2.dispatcher.ng.filter.StrutsPrepareAndExecuteFilter</filter-class>          </filter>          <filter-mapping>            <filter-name>Struts2</filter-name>            <url-pattern>/*</url-pattern><!--'/*' 过滤所有请求 -->          </filter-mapping>        3、编写页面index.jsp    4、配置控制器(action) LoginAction  继承 Actionsupper        重写父类的excute()方法    5、配置struts.xml(核心文件);可以参照struts-default.xml        6、处理完逻辑之后返回相应的字符串success、error跳转到相应的页面


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