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【POJ 2484 A Funny Game】+ 博弈

2019-11-11 05:51:49
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A Funny Game Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 5487 Accepted: 3444

Description Alice and Bob decide to play a funny game. At the beginning of the game they pick n(1 <= n <= 106) coins in a circle, as Figure 1 shows. A move consists in removing one or two adjacent coins, leaving all other coins untouched. At least one coin must be removed. Players alternate moves with Alice starting. The player that removes the last coin wins. (The last player to move wins. If you can’t move, you lose.)

Figure 1

Note: For n > 3, we use c1, c2, …, cn to denote the coins clockwise and if Alice remove c2, then c1 and c3 are NOT adjacent! (Because there is an empty place between c1 and c3.)

Suppose that both Alice and Bob do their best in the game. You are to write a PRogram to determine who will finally win the game.

Input There are several test cases. Each test case has only one line, which contains a positive integer n (1 <= n <= 106). There are no blank lines between cases. A line with a single 0 terminates the input.

Output For each test case, if Alice win the game,output “Alice”, otherwise output “Bob”.

Sample Input

1 2 3 0

Sample Output

Alice Alice Bob

3,4先手必败,大于4当先手取后,后手都可以将剩下的分成完全相同的两份,先手必败

AC代码 :

#include<cstdio>int main(){ int N; while(scanf("%d",&N) != EOF && N){ if(N <= 2) printf("Alice/n"); else printf("Bob/n"); } return 0;}
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