iOS UIWebView 通过 cookie 完成自动登录实例

2019-10-21 18:46:56

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1、相关介绍

iOS在UIWebView中获取的cookie的方法：NSHTTPCookieStorage * nCookies = [NSHTTPCookieStorage sharedHTTPCookieStorage];

再具体获取某个域的cookie：NSArray* cookiesURL = [nCookies cookiesForURL:[NSURL URLWithString:@"你的URL"]];

通过[[NSHTTPCookieStorage sharedHTTPCookieStorage] setCookie:userCookie]方法将 cookies来保存起来，但是这样虽然可以保存cookies但是你应用退出之后还是会丢失(其实是cookies过期的问题)，做好的方法是把cookies放到NSUserDefaults保存起来.

2、实现

1.在UIWebView的代理方法中实现获取cookies并将cookies放到NSUserDefaults保存起来：- (void)webViewDidFinishLoad:(UIWebView*)webView中写入

- (void)webViewDidFinishLoad:(UIWebView*)webView{    NSArray *nCookies = [[NSHTTPCookieStoragesharedHTTPCookieStorage] cookies];  for (NSHTTPCookie *cookie in nCookies){    if ([cookie isKindOfClass:[NSHTTPCookie class]]){            if ([cookie.name isEqualToString:@"PHPSESSID"]) {        NSNumber *sessionOnly =[NSNumber numberWithBool:cookie.sessionOnly];        NSNumber *isSecure = [NSNumber numberWithBool:cookie.isSecure];        NSArray *cookies = [NSArray arrayWithObjects:cookie.name, cookie.value, sessionOnly, cookie.domain, cookie.path, isSecure, nil];        [[NSUserDefaults standardUserDefaults] setObject:cookies forKey:@"cookies"];        break;      }    }  }}

2.获取cookies：运行之后，UIWebView加载url之前获取保存好的cookies，并设置cookies，

NSArray *cookies =[[NSUserDefaults standardUserDefaults] objectForKey:@"cookies"];  if (cookies.count >0) {    NSMutableDictionary *cookieProperties = [NSMutableDictionarydictionary];    [cookieProperties setObject:[cookies objectAtIndex:0] forKey:NSHTTPCookieName];    [cookieProperties setObject:[cookies objectAtIndex:1] forKey:NSHTTPCookieValue];    [cookieProperties setObject:[cookies objectAtIndex:3] forKey:NSHTTPCookieDomain];    [cookieProperties setObject:[cookies objectAtIndex:4] forKey:NSHTTPCookiePath];    NSHTTPCookie *cookieuser = [NSHTTPCookiecookieWithProperties:cookieProperties];    [[NSHTTPCookieStorage sharedHTTPCookieStorage] setCookie:cookieuser];  }

注意：要在[self.webView loadRequest:req];之前设置获取cookies！

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注：相关教程知识阅读请移步到IOS开发频道。

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