实例讲解一个shell处理db2数据库的程序

#SQL文定义SQL="SELECT AAA, BBB, CCC FROM MYTBL1"#执行SQLSDATA=`db2 "$SQL"`#返回值判断if [ $? -ne 0 ]then#显示db2返回的错误信息echo "$SDATA"exit 1fi#对取得的数据进行处理。echo "$SDATA" | sed -e '4,/^$/!d;/^$/d' |while read AAA BBB CCCdo  echo "AAA IS $AAA, BBB IS $BBB, CCC IS $CCC"done#取得数据件数echo "$SDATA" | sed -n -e '/^$/{1,3d;n;s/[^0-9]*/([0-9]*/)[^0-9]*//1/;p;}' | read CNTecho "The count of selected data is $CNT."exit 0

SQL="UPDATE MYTBL1 SET AAA='2005',BBB='05',CCC='12'"#执行SQLSDATA=`db2 -a "$SQL"`#取得SQLCODEecho "$SDATA" | sed -n -e 's/^.*sqlcode: /([-,0-9][0-9]*/).*//1/p' | read SQLCODEecho "Sqlcode is $SQLCODE."#取得SQLSTATEecho "$SDATA" | sed -n -e 's/^.*sqlstate: /([-,0-9][0-9]*/).*//1/p' | read SQLSTATEecho "Sqlstate is $SQLSTATE."#取得更新件数(即sqlerrd的第三个值)echo "$SDATA" | sed -n -e '/sqlerrd/s/^.*(3) /([-,0-9][0-9]*/).*//1/p' | read UPDCNTecho "Updated data's count is $UPDCNT."#取得sqlerrd的第五个值echo "$SDATA" | sed -n -e '/sqlerrd/{n;s/^.*(5) /([-,0-9][0-9]*/).*//1/;p;}' | read SQLERRD5echo "Sqlerrd(5) is $SQLERRD5."