list解析
先看下面的例子,这个例子是想得到1到9的每个整数的平方,并且将结果放在list中打印出来
>>> power2 = []>>> for i in range(1,10):... power2.append(i*i)... >>> power2[1, 4, 9, 16, 25, 36, 49, 64, 81]
python有一个非常有意思的功能,就是list解析,就是这样的:
>>> squares = [x**2 for x in range(1,10)]>>> squares[1, 4, 9, 16, 25, 36, 49, 64, 81]
看到这个结果,看官还不惊叹吗?这就是python,追求简洁优雅的python!
其官方文档中有这样一段描述,道出了list解析的真谛:
List comprehensions provide a concise way to create lists. Common applications are to make new lists where each element is the result of some operations applied to each member of another sequence or iterable, or to create a subsequence of those elements that satisfy a certain condition.
还记得前面一讲中的那个问题吗?
找出100以内的能够被3整除的正整数。
我们用的方法是:
aliquot = []for n in range(1,100): if n%3 == 0: aliquot.append(n)print aliquot
好了。现在用list解析重写,会是这样的:
>>> aliquot = [n for n in range(1,100) if n%3==0]>>> aliquot[3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63, 66, 69, 72, 75, 78, 81, 84, 87, 90, 93, 96, 99]
震撼了。绝对牛X!
其实,不仅仅对数字组成的list,所有的都可以如此操作。请在平复了激动的心之后,默默地看下面的代码,感悟一下list解析的魅力。
>>> mybag = [' glass',' apple','green leaf '] #有的前面有空格,有的后面有空格>>> [one.strip() for one in mybag] #去掉元素前后的空格['glass', 'apple', 'green leaf']enumerate
这是一个有意思的内置函数,本来我们可以通过for i in range(len(list))的方式得到一个list的每个元素编号,然后在用list[i]的方式得到该元素。如果要同时得到元素编号和元素怎么办?就是这样了:
>>> for i in range(len(week)):... print week[i]+' is '+str(i) #注意,i是int类型,如果和前面的用+连接,必须是str类型... monday is 0sunday is 1friday is 2
python中提供了一个内置函数enumerate,能够实现类似的功能
>>> for (i,day) in enumerate(week):... print day+' is '+str(i)... monday is 0sunday is 1friday is 2
算是一个有意思的内置函数了,主要是提供一个简单快捷的方法。
官方文档是这么说的:
代码如下:
Return an enumerate object. sequence must be a sequence, an iterator, or some other object which supports iteration. The next() method of the iterator returned by enumerate() returns a tuple containing a count (from start which defaults to 0) and the values obtained from iterating over sequence:
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