首页 > 编程 > Python > 正文

python实现批量转换文件编码(批转换编码示例)

2020-02-23 05:06:54
字体:
来源:转载
供稿:网友

代码如下:
# -*- coding:utf-8 -*-
__author__ = 'walkskyer'

import os
import glob

class Encoding:
    def __init__(self):
        #文件扩展名
        self.ext = ".*"
        #编码
        self.srcEncoding=None
        self.dstEncoding=None

    def convertEncoding(self, content, srcEncoding=None, dstEncoding=None):
        return content.decode(self.srcEncoding).encode(self.dstEncoding)

    def processDirectory(self, args, dirname, filenames):
        print 'Directory', dirname
        for filename in filenames:
            if not os.path.isdir(dirname+'/'+filename):
                if filename.endswith(self.ext) or self.ext == ".*":
                    print ' File', filename
                    self.f2f(dirname+'/'+filename)

    def f2f(self, filepath, srcEncoding=None, dstEncoding=None):
        try:
            f1 = open(filepath, 'rb')
            temp = f1.read()
            f1.close()
            f2 = open(filepath, 'wb')
            f2.write(temp.decode(self.srcEncoding).encode(self.dstEncoding))
            f2.close()
            print '转码成功'
        except Exception, e:
            print e


    def colectFileType(self, dirname, fileType):
        for filename in glob.glob(r'*.'+fileType):
            print filename

    def setExt(self, ext):
        if not ext.startswith('.'):
            ext = "." + ext
        self.ext = ext

    def setSRC(self, encoding):
        self.srcEncoding=encoding

    def setDST(self, encoding):

发表评论 共有条评论
用户名: 密码:
验证码: 匿名发表