python ip正则式

2020-02-23 04:42:43

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ip正则式为：r'(([12][0-9][0-9]|[1-9][0-9]|[1-9])/.){3,3}([12][0-9][0-9]|[1-9][0-9]|[1-9])'
以下为一个示例
#-*- coding:utf-8 -*-
import re
def ip():
'验证IP的正则式'
def match_group(p):
s = '''211.210.209.108
gan ffad1.210.2.108
d ffad1.210.2.109afa'''
com = re.compile(p)
lst_m = com.finditer(s)
for m in lst_m:
print m.group()
p = r'(([12][0-9][0-9]|[1-9][0-9]|[1-9])/.){3,3}([12][0-9][0-9]|[1-9][0-9]|[1-9])'
match_group(p)
def group():
'''若存在多个匹配，可以用finditer来获取到多个组'''
def match(p):
s = 'Isaac Newton, physicist, huang zhijun'
mo = re.compile(p)
m = mo.search(s)
if not m:
print 'no match'
else:
print mo.findall(s)
print 'm.group(0):', m.group(0)
# print 'm.group(1):', m.group(1)
# print 'm.group(2):', m.group(2)
m_ite = mo.finditer(s)
for ite in m_ite:
print 'ite.group(0)', ite.group(0)
print 'ite.group(1)', ite.group(1)
print 'ite.group(2)', ite.group(2)
# p = r'(/w+) (/w+)'
p = r'(/w+) (/w+)'
match(p)
if __name__ == '__main__':
ip()
# group()

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