基于C语言实现简单的走迷宫游戏

#include <cstdio>#include <deque>#include <windows.h>using namespace std;class node{public: int x,y; int lastOpt;};deque<node> sta;int x,y;int endx,endy;int mapW,mapH;int steps;int xopt[5]= {0,0,1,0,-1};int yopt[5]= {0,1,0,-1,0};int map[100][100]={ };void init(){ x = 1; y = 1; endx = 1; endy = 9; mapH = 10; mapW = 10; for(int i=0; i<=mapH; i++)  for(int j=0; j<=mapW; j++)  {   if(i==0 ||j==0 ||i==mapH||j==mapW)    map[i][j]=-1;  }  steps=0; map[1][2]=-1; map[2][2]=-1; map[3][2]=-1; map[4][2]=-1;  map[6][2]=-1; map[7][2]=-1; map[8][2]=-1; map[9][2]=-1; map[9][3]=-1; map[8][3]=-1; map[1][4]=-1; map[3][4]=-1; map[4][4]=-1; map[5][4]=-1; map[6][4]=-1; map[7][4]=-1; map[1][6]=-1; map[2][6]=-1; map[3][6]=-1; map[4][6]=-1; map[5][6]=-1; map[6][6]=-1; map[7][6]=-1; map[8][6]=-1; map[8][7]=-1; map[8][8]=-1; map[7][8]=-1; map[6][8]=-1; map[5][8]=-1; map[4][8]=-1; map[3][8]=-1; map[2][8]=-1; map[1][8]=-1;  map[endx][endy]=5;} void dis(){ system("cls"); int ori = map[x][y]; map[x][y]=1; for(int i=0; i<=mapH; ++i) {  for(int j=0; j<=mapW; ++j)  {   if(map[i][j]==0)    printf(" ");   else if(map[i][j]==-1)    printf(" #");   else if(map[i][j]==1)    printf(" @");   else if(map[i][j]==2)    printf(" .");   else if(map[i][j]==5)    printf(" !");  }  cout<<i<<endl; } for(int j=0; j<=mapW; ++j)  cout<<j<<" "; printf("/n/n > steps:%d Exit:(%d,%d)/n",steps,endx,endy); map[x][y] = ori;}int can(int n){ if(map[x+xopt[n]][y+yopt[n]] == 0 || map[x+xopt[n]][y+yopt[n]] == 5)  return 1; return 0; }void visit(int n){ map[x][y]=2; x+=xopt[n]; y+=yopt[n]; node tem; tem.x = x; tem.y = y; tem.lastOpt = n; sta.push_back(tem); steps++;}int main(){ init(); node tem; while( x != endx || y!=endy) {   int cans = 0;  for(int i=1; i<=4; i++)  {   if(can(i))   {    cans = 1;    visit(i);    break;   }  }  if(!cans)  {   if(!sta.empty())   {    tem = sta.back();    map[tem.x][tem.y]=0;    sta.pop_back();   }   else   {    map[x][y]=2;    x+=xopt[tem.lastOpt];    x+=yopt[tem.lastOpt];    dis();    break;   }   }   dis();  Sleep(500);  } if(x==endx && y == endy) cout<<"/n > i am finished..../n"; else cout<<"/n > i am finished...but i can't find the right way/n"; return 0;}