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C语言实现俄罗斯方块小游戏

2020-01-26 13:59:37
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C语言实现俄罗斯方块小游戏的制作代码,具体内容如下

#include <stdio.h> #include <stdlib.h> #include <unistd.h>   #define TTY_PATH "/dev/tty" #define STTY_ON "stty raw -echo -F" #define STTY_OFF "stty -raw echo -F"  int map[21][14]; char direct;  int node[7][4][16]={  {{0,0,0,0,1,1,1,1,0,0,0,0,0,0,0,0},//长方形   {0,1,0,0,0,1,0,0,0,1,0,0,0,1,0,0},   {0,0,0,0,1,1,1,1,0,0,0,0,0,0,0,0},   {0,1,0,0,0,1,0,0,0,1,0,0,0,1,0,0}},  {{1,1,0,0,1,1,0,0,0,0,0,0,0,0,0,0},//正方形   {1,1,0,0,1,1,0,0,0,0,0,0,0,0,0,0},   {1,1,0,0,1,1,0,0,0,0,0,0,0,0,0,0},   {1,1,0,0,1,1,0,0,0,0,0,0,0,0,0,0}},  {{0,1,0,0,1,1,1,0,0,0,0,0,0,0,0,0},//3边加一中点   {0,1,0,0,0,1,1,0,0,1,0,0,0,0,0,0},   {0,0,0,0,1,1,1,0,0,1,0,0,0,0,0,0},   {0,1,0,0,1,1,0,0,0,1,0,0,0,0,0,0}},  {{0,1,1,0,0,1,0,0,0,1,0,0,0,0,0,0},//右锄头型   {0,0,0,0,1,1,1,0,0,0,1,0,0,0,0,0},   {0,1,0,0,0,1,0,0,1,1,0,0,0,0,0,0},   {1,0,0,0,1,1,1,0,0,0,0,0,0,0,0,0}},  {{1,1,0,0,0,1,0,0,0,1,0,0,0,0,0,0},//左锄头型   {0,0,1,0,1,1,1,0,0,0,0,0,0,0,0,0},   {0,1,0,0,0,1,0,0,0,1,1,0,0,0,0,0},   {0,0,0,0,1,1,1,0,1,0,0,0,0,0,0,0}},  {{0,1,0,0,0,1,1,0,0,0,1,0,0,0,0,0},//右曲折型   {0,1,1,0,1,1,0,0,0,0,0,0,0,0,0,0},   {0,1,0,0,0,1,1,0,0,0,1,0,0,0,0,0},   {0,1,1,0,1,1,0,0,0,0,0,0,0,0,0,0}},  {{0,1,0,0,1,1,0,0,1,0,0,0,0,0,0,0},//左曲折型   {1,1,0,0,0,1,1,0,0,0,0,0,0,0,0,0},   {0,1,0,0,1,1,0,0,1,0,0,0,0,0,0,0},   {1,1,0,0,0,1,1,0,0,0,0,0,0,0,0,0}}  };  typedef struct block {  int x;  int y;  int blockType;  int blockDirect; }Block; Block bl;  void init_map()//初始化边框 {  int i,j;  for(i=0; i<21; i++)  for(j=0; j<14; j++)  {   if(j==0 || j==13)   map[i][j] = 200;   else if(i==20)   map[i][j] = 201;   else   map[i][j] = 0;  } } void new_block()//生成随机的俄罗斯方块 {  int blockType = rand()%7;  int blockDirect = rand()%4;  int x = 1;  int y = 5;  bl.x = x;  bl.y = y;  bl.blockType = blockType;  bl.blockDirect = blockDirect; }  void input()//将移动后的俄罗斯方块,导入地图中作标记 {  int i, j;  for(i=0; i<4; i++)  for(j=0; j<4; j++)   if(node[bl.blockType][bl.blockDirect][i*4+j]==1)   {   map[bl.x+i][bl.y+j] = 1;   } } void output()//移动时,将之前俄罗斯方块在地图信息清空。 {  int i, j;  for(i=0; i<4; i++)  for(j=0; j<4; j++)   if(node[bl.blockType][bl.blockDirect][i*4+j]==1)   {   map[bl.x+i][bl.y+j] = 0;   } }  void change()//俄罗斯方格在碰撞后融入,固定 {  int i, j;  for(i=0; i<4; i++)  for(j=0; j<4; j++)   if(node[bl.blockType][bl.blockDirect][i*4+j]==1)   {   map[bl.x+i][bl.y+j] = 10;   }  for(j=1; j<13; j++)  if(map[5][j] == 10)  {   system("clear");   printf("game over !!!!!!!!!/n");   exit(1);  } }   void print_map()//打印地图,显示信息 {  int i,j;  for(i=5; i<21; i++)  {  for(j=0; j<14; j++)  {   if(map[i][j]==200)//左右边界   printf("#");   else if(map[i][j]==201)//下边界   printf(" # ");   else if(map[i][j]==0)//空白地   printf(" ");   else if(map[i][j]==1)//移动的俄罗斯方块   printf(" * ");   else if(map[i][j]==10)//固定的俄罗斯方块   printf(" @ ");  }  printf("/n");  } } void delLine(int n)//消行 {  int i,j;  for(j = 1; j<13; j++)  map[n][j] = 0;  for(i = n; i>5 ; i--)  for(j = 1; j<13; j++)  if(map[i-1][j] != 1)  map[i][j] = map[i-1][j]; }  void isFillLine()//是否满足消行条件 {   int i,j;  int fals;  for(i=19; i>5; i--)  {  fals = 1;  for(j=1; j<13; j++)  {   if(map[i][j] != 10)   {   fals = 0;    continue;   }  }  if(fals)  {   delLine(i);  }  } } void down()//下移 {  int i, j;  int fale = 1;  for(i=3; i>=0; i--)  for(j=0; j<4; j++)   if(node[bl.blockType][bl.blockDirect][i*4+j] == 1)   if(map[bl.x+i+1][bl.y+j] == 10 || map[bl.x+i+1][bl.y+j] == 201)   {    change();    fale = 0;    new_block();    isFillLine();     return;   }  if(fale)  {  output();  bl.x += 1;  input();  }    } void right()//右移 {  int i, j;  int fale = 1;  for(i=3; i>=0; i--)  for(j=0; j<4; j++)   if(node[bl.blockType][bl.blockDirect][i*4+j] == 1)   if(map[bl.x+i][bl.y+j+1] == 10 || map[bl.x+i][bl.y+j+1] == 200)   {    fale = 0;    return;   }  if(fale)  {  output();  bl.y += 1;  input();  }  } void left()//左移 {  int i, j;  int fale = 1;  for(i=3; i>=0; i--)  for(j=0; j<4; j++)   if(node[bl.blockType][bl.blockDirect][i*4+j] == 1)   if(map[bl.x+i][bl.y+j-1] == 10 || map[bl.x+i][bl.y+j-1] == 200)   {    fale = 0;    return;   }  if(fale)  {  output();  bl.y -= 1;  input();  }  }  void change_block()//俄罗斯方块变形 {  int i,j;  output();  int fals = 1;  bl.blockDirect += 1;  bl.blockDirect %= 4;  for(i=0; i<4; i++)  for(j=0; j<4; j++)  if(node[bl.blockType][bl.blockDirect][i*4+j]==1)   if(map[bl.x+i][bl.y+j] != 0 )   {   fals = 0;   break;   }  if(fals)  {  input();  }else  {  bl.blockDirect -= 1;  input();  } }  char in_direct()//非堵塞输入 {  fd_set fd;  struct timeval tv;  char ch;  FD_ZERO(&fd);  FD_SET(0, &fd);  tv.tv_sec = 0;  tv.tv_usec = 10;  if(select(1, &fd ,NULL, NULL, &tv) > 0)  {   ch = getchar();  }  return ch; } int main()//q 退出游戏,a,d 左右移动,空格变形 {  srand(time(NULL));  init_map();  new_block();  input();  char ch;  int num = 0;  while(1)  {  usleep(500000);  system(STTY_ON TTY_PATH);  ch = in_direct();  system(STTY_OFF TTY_PATH);  system("clear");  if(ch == 'a' && num <= 1)  {   left();   print_map();   num++;   continue;  }else if(ch == 'd' && num <= 1)  {   right();   print_map();   num++;   continue;  }else if(ch == ' ' && num <= 1 )  {   change_block();   print_map();   num++;   continue;  }else if(ch == 'q')  {   system("clear");   printf("gave over!!!!!/n");   exit(0);  }  down();  print_map();  num = 0;   }  return 0; }

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