C语言实现直角坐标转换为极坐标的方法

#include<stdio.h>#include<math.h>struct complex_s{    double x,y;};double real_part(struct complex_s z){    return z.x;}double img_part(struct complex_s z){    return z.y;}double magnitude(struct complex_s z){    return sqrt(z.x*z.x + z.y*z.y);}double angle(struct complex_s z){    return atan2(z.y, z.x);}struct complex_s make_from_real_img(double x, double y){    struct complex_s z;    z.x = x;    z.y = y;    return z;}struct complex_s make_from_mag_ang(double r, double A){    struct complex_s z;    z.x = r * cos(A);    z.y = r * sin(A);    return z;}struct complex_s add_complex(struct complex_s z1,struct complex_s z2){    return make_from_real_img(real_part(z1)+real_part(z2),        img_part(z1) + img_part(z2));}struct complex_s sub_complex(struct complex_s z1,struct complex_s z2){    return make_from_real_img(real_part(z1)-real_part(z2),        img_part(z1) - img_part(z2));}struct complex_s mul_complex(struct complex_s z1,struct complex_s z2){    return make_from_mag_ang(real_part(z1)*real_part(z2),        img_part(z1) + img_part(z2));}struct complex_s div_complex(struct complex_s z1,struct complex_s z2){    return make_from_mag_ang(real_part(z1)/real_part(z2),        img_part(z1) + img_part(z2));}int main(void){    struct complex_s z1 = {3.0,4.0};    struct complex_s z2= {2.0,5.0};    struct complex_s x;    x = add_complex(z1,z2);    printf("x={%f,%f}",x.x,x.y);    return 0;}

[root@localhost struct]# ./jizuobiao.outx={5.000000,9.000000}