C语言实现两个矩阵相乘

#include "stdafx.h"#include "windows.h"void Multi(int * left, int * right, int * result, int f1, int f2, int s1, int s2);int main(){ int i, j; int a[4][3] =  { {1,2,3},  {4,5,6},  {7,8,9},  {1,2,3}}; int b[3][3] = { { 1,2,3 }, { 4,5,6 }, {7,8,9} }; //c矩阵为a矩阵与b矩阵的乘积 int c[4][3]; //计算两个矩阵相乘 Multi(a[0], b[0],c[0], 4, 3, 3, 3); //输出c矩阵 for (i = 0; i < 4; i++) {  for(j=0;j<3;j++)   printf("%4d ", c[i][j]);  printf("/n"); } system("pause"); return 0;}//矩阵相乘算法，最后四个参数是两个相乘的矩阵的行数和列数void Multi(int * left, int * right, int * result,int f1, int f2, int s1, int s2){ //int a[f1][f2], b[s1][s2], c[f1][s2]; //a[i][j]==a[i*f2+j] //由矩阵相乘，要求f2=s1，以下用f2 for (int i = 0; i < f1; i++) //i表示第i行 {  for (int j = 0; j < s2; j++) //j表示第j列  {   result[i*f2 + j] = 0;  //在这里 result[i][j] = result[i*f2+j];   for(int p=0;p<f2;p++)   {    result[i*f2 + j] +=left[i*f2+p]*right[p*f2+j];   }  } }}