C语言测试n的阶乘和x的n次方

/*************************************************************************    > File Name: 2.c    > Author:     > Mail:     > Created Time: Wed 12 Dec 2018 09:03:22 AM CST ************************************************************************/#include<stdio.h>double fact(int n){    double s = 1.0;  for(int i=1; i<= n; i++)    {        s=s*i;    }     return s;}double mypow(double x,int n){           double s = 1.0;  //printf("%lf %d/n",x,n);  if(n == 0)    {          return 1.0;   }              if(n == 1)    {          return x;                                          }  s = x;  for(int i =0;i<n-1;i++)  {          s = x*s;    }  //printf("%lf /n",s);  return s;   }void main(void){  double x = 0.0;  int n = 0;  double s;  scanf("%lf %d",&x,&n);  //printf("%lf/n",mypow(-1.0,2));  if(n == 1)  {    s = x;  }  else  {    s = x;    for(int i=2;i<=n;i++)    {      s = s+ mypow(-1.0,i-1)*mypow(x,i)/fact(i);    }  }  printf("%.4lf/n",s);}

#include <stdio.h>int main (){double x, ret, tmp1, tmp2;int n, i, j;while (~scanf("%lf %d", &x, &n)){ret = 0;for (i = 1; i <= n; i++){tmp1 = 1;for (j = 1; j <= i; j++){tmp1 *= x;}tmp2 = 1;for (j = 1; j <= i; j++){tmp2 *= j;}if (i % 2 == 1){ret += tmp1 / tmp2;}else{ret -= tmp1 / tmp2;}}printf("%.04f/n", ret);}return 0;}