C语言用函数实现电话簿管理系统

#include<stdio.h>#include<string.h>typedef struct Contact { char name[21]; char phone[21]; char QQ[21];} CONTACT;int AddContact(CONTACT cons[],int num){ num++; printf("请输入姓名(最长20个字符)："); scanf("%s",&cons[num].name); printf("请输入QQ(最长20位)："); scanf("%s",&cons[num].QQ); printf("请输入手机号码（最长20位）："); scanf("%s",&cons[num].phone); printf("添加成功！/n"); return num;}void showContact(CONTACT cons[],int num){ printf("共有 %d 个联系人信息：/n", num); printf("===============================================================/n"); printf("No./t/t姓名/t/tQQ号/t/t联系电话/n"); printf("---------------------------------------------------------------/n"); for(int i = 1; i <= num; i++){ printf("%d/t/t%s/t/t%s/t%s/t/t/n", i, cons[i].name, cons[i].QQ, cons[i].phone); } printf("===============================================================/n");}int DelContact(CONTACT cons[],int num){ int i = 1; showContact(cons,num); printf("请输入要删除的联系人序号:"); scanf("%d",&i); if(i < 1 || i > num) printf("序号输入错误，删除失败！/n"); else { for(int j = i ; j < num; j++) { cons[j] = cons[j  + 1]; } printf("联系人信息已删除！/n"); num--; } return num;}void findContact(CONTACT cons[],int num){ char f_name[25]; int count = 0; int i = 1; printf("请输入要查找的联系人姓名:"); scanf("%s",f_name); printf("===============================================================/n"); printf("No./t/t姓名/t/tQQ号/t/t联系电话/n"); printf("---------------------------------------------------------------/n"); for(i ; i <= num; i++) { if(strcmp(cons[i].name,f_name) == 0) {  count++;  printf("%d/t/t%s/t/t%s/t%s/t/t/n", i, cons[i].name, cons[i].QQ, cons[i].phone); } } printf("===============================================================/n"); printf("共查询到%d条联系人数据/n",count);}void alterContact(CONTACT cons[], int num){ int i; printf("请输入要修改的联系人序号："); scanf("%d", &i); if(i < 1 || i > num) { printf("序号输入有误，请重新输入！/n"); alterContact(cons, num); } else { printf("请输入姓名(最长20个字符)："); scanf("%s",&cons[i].name); printf("请输入QQ(最长20位)："); scanf("%s",&cons[i].QQ); printf("请输入手机号码（最长20位）："); scanf("%s",&cons[i].phone); }}int main(){ CONTACT cons[100]; int num = 0; int op = -1; while(1){ int op; printf("/t*****菜单*****/t/n"); printf("------------------------------/n"); printf("/t1.添加联系人/n"); printf("/t2.删除联系人/n"); printf("/t3.显示所有联系人/n"); printf("/t4.查找联系人/n"); printf("/t5.修改联系人/n"); printf("/t0.退出系统/n"); printf("------------------------------/n"); printf("请输入您的选择(0 ~ 5)："); scanf("%d",&op); if(op == 0)  break; switch(op){  case 1:  num = AddContact(cons,num);  break;  case 2:  num = DelContact(cons,num);  break;  case 3:  showContact(cons,num);  break;  case 4:  findContact(cons,num);  break;  case 5:  showContact(cons, num);  alterContact(cons,num);  printf("修改成功！/n”);  break; } } return 0;}