C#模拟MSN窗体抖动的实现代码

//第一种抖动private void button1_Click(object sender, EventArgs e){  int recordx = this.Left;      //保存原来窗体的左上角的x坐标  int recordy = this.Top;       //保存原来窗体的左上角的y坐标  Random random = new Random();     for (int i = 0; i < 100; i++)  { int x = random.Next(rand); int y = random.Next(rand); if (x % 2 == 0) {   this.Left = this.Left + x; } else {   this.Left = this.Left - x; } if (y % 2 == 0) {   this.Top = this.Top + y; } else {   this.Top = this.Top - y; } this.Left = recordx;      //还原原始窗体的左上角的x坐标 this.Top = recordy;       //还原原始窗体的左上角的y坐标  }  }//第二种抖动private void button2_Click(object sender, EventArgs e){  int recordx = this.Left;  int recordy = this.Top;  Random random = new Random();  for (int i = 0; i < 50; i++)  { int x = random.Next(rand); int y = random.Next(rand); if (x % 2 == 0) {   this.Left = this.Left + x; } else {   this.Left = this.Left - x; } if (y % 2 == 0) {   this.Top = this.Top + y; } else {   this.Top = this.Top - y; } System.Threading.Thread.Sleep(1);  }  this.Left = recordx;  this.Top = recordy;}