C#迷你猜数实例分析

using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Threading.Tasks; namespace 迷你猜数 {  class Program  {   static void Main(string[] args)   {    List<int> LisData = GetData();    LisData = FilterData(LisData, 4659, 0, 1);    LisData = FilterData(LisData, 8763, 0, 1);    LisData = FilterData(LisData, 1035, 0, 1);    LisData = FilterData(LisData, 3249, 1, 1);    LisData = FilterData(LisData, 0497, 0, 2);    LisData = FilterData(LisData, 9148, 0, 2);    foreach(var num in LisData)    {     Console.WriteLine(num);    }    Console.ReadKey();   }   /// <summary>   /// 获取所有可用数据   /// </summary>   /// <returns></returns>   private static List<int> GetData()   {    List<int> LisData = new List<int>();    for (int i = 0; i < 10; i++)    {     for (int j = 0; j < 10; j++)     {      for (int k = 0; k < 10; k++)      {       for (int m = 0; m < 10; m++)       {        if((i!=j) && (i!=k) && (i!=m) && (j!=k) && (j!=m) && (k!=m))        {         LisData.Add(i * 1000 + j * 100 + k * 10 + m);        }       }      }     }    }    return LisData;   }   private static List<int> FilterData(List<int> LisData,int Num,int a,int b)   {    List<int> lisDataNum=new List<int>();    int[] LisNum = new int[4];    //将Num拆分成一个数组    int[] Numnum = SplitNum(Num);    foreach(var Data in LisData)    {     int aNum = 0;     int bNum = 0;     //将Data拆分成一个数组     LisNum = SplitNum(Data);     #region 求a，b的个数     for (int i=0;i<4;i++)     {      //求a的个数      if(Numnum[i]==LisNum[i])      {       aNum++;      }      //求b的个数      for(int j=0;j<4;j++)      {       if(Numnum[i]==LisNum[j])       {        bNum++;       }      }     }     bNum -= aNum;     #endregion 求a,b的个数     //判断a,b     if((aNum==a)&&(bNum==b))     {      lisDataNum.Add(Data);     }    }    return lisDataNum;   }   /// <summary>   /// 拆分四位数   /// </summary>   /// <param name="Num"></param>   /// <returns></returns>   private static int[] SplitNum(int Num)   {    int[] Numnu = new int[4];    for (int i = 0; i < 4; i++)    {     Numnu[i] = Num % 10;     Num = Num / 10;    }    return Numnu;   }  } }