C#结合JavaScript实现秒杀倒计时的方法

private string Dtime() {  byte tempB = (byte)DateTime.Now.DayOfWeek;  byte dayByte = (byte)DayOfWeek.Wednesday;  DateTime wednesdayNow = DateTime.Now.AddDays(dayByte - tempB); //本星期三  DateTime returnTime = new DateTime ();  if (DateTime.Now.DayOfWeek < wednesdayNow.DayOfWeek)  {   //当前星期小于本星期三 获取本周星期三   returnTime = new DateTime(wednesdayNow.Year,wednesdayNow.Month,wednesdayNow.Day,10,0,0); }  else  {   //当前星期大于本星期三 获取下周星期三   DateTime nextWednesday = wednesdayNow.AddDays(7);//下周三   returnTime = new DateTime(nextWednesday.Year,nextWednesday.Month,nextWednesday.Day,10,0,0); }  return returnTime.ToString() }

$(document).ready(function() { $('body').everyTime('1s', function() { var nowDate = new Date(); var endDate = new Date($("#sp_next").html().replace(//-/g, "//")); //这个时间是上个方法返回的时间 var timeold = endDate.getTime() - nowDate.getTime(); var sectimeold = timeold / 1000 var secondsold = Math.floor(sectimeold); var msPerDay = 24 * 60 * 60 * 1000 var e_daysold = timeold / msPerDay var daysold = Math.floor(e_daysold); var e_hrsold = (e_daysold - daysold) * 24 + (daysold * 24); var hrsold = Math.floor(e_hrsold); var e_minsold = (e_hrsold - hrsold) * 60; var minsold = Math.floor((e_hrsold - hrsold) * 60); var seconds = Math.floor((e_minsold - minsold) * 60); if (hrsold > 0 && hrsold < 10) { hrsold = "0" + hrsold; } if (minsold < 10) { minsold = "0" + minsold; } if (seconds < 10) { seconds = "0" + seconds; } if (hrsold < 0) {  $(".seckill_time").html("0");  $(".seckill_minute").html("0");  $(".seckill_second").html("0"); } else {  $(".seckill_time").html("").html(hrsold);  $(".seckill_minute").html("").html(minsold);  $(".seckill_second").html("").html(seconds); } });});