C#绘制中国国旗的方法

2020-01-24 01:32:57

字体：大中小

来源：转载

供稿：网友

本文实例讲述了C#绘制中国国旗的方法。分享给大家供大家参考。具体如下：

程序运行截图：

中国国旗被定义在《GB：12982-2004》中，以下是从维基百科条目中华人民共和国国旗中截的一张图，标出了五颗星大致的位置。

建立一个空的C# Windows窗体应用程序，窗体取名FormMain，在窗体中放一个PictureBox，取名为picFlagOfChina，并将Dock属性设置为Fill。程序代码中用到了窗体事件Load和Resize，程序代码如下：

using System;using System.Collections.Generic;using System.ComponentModel;using System.Data;using System.Drawing;using System.Linq;using System.Text;using System.Windows.Forms;namespace ChineseFlag{ public partial class FormMain : Form {  public FormMain()  {   InitializeComponent();  }  private void FormMain_Load(object sender, EventArgs e)  {   PaintFlag();  }  //修改窗体大小时发生  private void FormMain_Resize(object sender, EventArgs e)  {   PaintFlag();  }  /// <summary>  /// 在图片框 picFlagOfChina 中绘制国旗  /// </summary>  private void PaintFlag()  {   picFlagOfChina.BackColor = Color.Red;   picFlagOfChina.Image = new Bitmap(    picFlagOfChina.Width, picFlagOfChina.Height);   Graphics g = Graphics.FromImage(picFlagOfChina.Image);   Point[] p = new Point[] { };   p = PentacleA(this.Width, this.Height);   g.FillPolygon(Brushes.Yellow, p);   p = PentacleB(this.Width, this.Height);   g.FillPolygon(Brushes.Yellow, p);   p = PentacleC(this.Width, this.Height);   g.FillPolygon(Brushes.Yellow, p);   p = PentacleD(this.Width, this.Height);   g.FillPolygon(Brushes.Yellow, p);   p = PentacleE(this.Width, this.Height);   g.FillPolygon(Brushes.Yellow, p);  }  //大星  private Point[] PentacleA(int width, int height)  {   return new Point[]    {     new Point((int)(width / 30.0 * 5), (int)(height / 20.0 * 2)),    new Point((int)(width / 30.0 * 5.7), (int)(height / 20.0 * 4.1)),    new Point((int)(width / 30.0 * 8), (int)(height / 20.0 * 4.1)),    new Point((int)(width / 30.0 * 6), (int)(height / 20.0 * 5.3)),    new Point((int)(width / 30.0 * 6.8), (int)(height / 20.0 * 7.3)),    new Point((int)(width / 30.0 * 5), (int)(height / 20.0 * 6.1)),    new Point((int)(width / 30.0 * 3.2), (int)(height / 20.0 * 7.3)),    new Point((int)(width / 30.0 * 4), (int)(height / 20.0 * 5.3)),    new Point((int)(width / 30.0 * 2), (int)(height / 20.0 * 4.1)),    new Point((int)(width / 30.0 * 4.3), (int)(height / 20.0 * 4.1)),   };  }  //工人星  private Point[] PentacleB(int width, int height)  {   return new Point[]    {     new Point((int)(width / 30.0 * 9.2), (int)(height / 20.0 * 2.5)),    new Point((int)(width / 30.0 * 9.6), (int)(height / 20.0 * 2)),    new Point((int)(width / 30.0 * 9.3), (int)(height / 20.0 * 1.4)),    new Point((int)(width / 30.0 * 9.95), (int)(height / 20.0 * 1.7)),    new Point((int)(width / 30.0 * 10.45), (int)(height / 20.0 * 1.1)),    new Point((int)(width / 30.0 * 10.36), (int)(height / 20.0 * 1.85)),    new Point((int)(width / 30.0 * 11), (int)(height / 20.0 * 2.1)),    new Point((int)(width / 30.0 * 10.34), (int)(height / 20.0 * 2.25)),    new Point((int)(width / 30.0 * 10.3), (int)(height / 20.0 * 2.95)),    new Point((int)(width / 30.0 * 9.9), (int)(height / 20.0 * 2.3))   };  }  //农民星  private Point[] PentacleC(int width, int height)  {   return new Point[]    {     new Point((int)(width / 30.0 * 11), (int)(height / 20.0 * 4.1)),    new Point((int)(width / 30.0 * 11.65), (int)(height / 20.0 * 3.8)),    new Point((int)(width / 30.0 * 11.55), (int)(height / 20.0 * 3.05)),    new Point((int)(width / 30.0 * 12.05), (int)(height / 20.0 * 3.6)),    new Point((int)(width / 30.0 * 12.7), (int)(height / 20.0 * 3.3)),    new Point((int)(width / 30.0 * 12.35), (int)(height / 20.0 * 3.98)),    new Point((int)(width / 30.0 * 12.9), (int)(height / 20.0 * 4.5)),    new Point((int)(width / 30.0 * 12.1), (int)(height / 20.0 * 4.3)),    new Point((int)(width / 30.0 * 11.8), (int)(height / 20.0 * 5)),    new Point((int)(width / 30.0 * 11.7), (int)(height / 20.0 * 4.2))   };  }  //小资星  private Point[] PentacleD(int width, int height)  {   return new Point[]    {     new Point((int)(width / 30.0 * 11.1), (int)(height / 20.0 * 6.7)),    new Point((int)(width / 30.0 * 11.8), (int)(height / 20.0 * 6.7)),    new Point((int)(width / 30.0 * 12), (int)(height / 20.0 * 6)),    new Point((int)(width / 30.0 * 12.2), (int)(height / 20.0 * 6.7)),    new Point((int)(width / 30.0 * 12.9), (int)(height / 20.0 * 6.7)),    new Point((int)(width / 30.0 * 12.35), (int)(height / 20.0 * 7.1)),    new Point((int)(width / 30.0 * 12.55), (int)(height / 20.0 * 7.8)),    new Point((int)(width / 30.0 * 12), (int)(height / 20.0 * 7.4)),    new Point((int)(width / 30.0 * 11.45), (int)(height / 20.0 * 7.8)),    new Point((int)(width / 30.0 * 11.65), (int)(height / 20.0 * 7.1))   };  }  //民资星(工人星向下平移7个单位)  private Point[] PentacleE(int width, int height)  {   return new Point[]    {     new Point((int)(width / 30.0 * 9.2), (int)(height / 20.0 * 9.5)),    new Point((int)(width / 30.0 * 9.6), (int)(height / 20.0 * 9)),    new Point((int)(width / 30.0 * 9.3), (int)(height / 20.0 * 8.4)),    new Point((int)(width / 30.0 * 9.95), (int)(height / 20.0 * 8.7)),    new Point((int)(width / 30.0 * 10.45), (int)(height / 20.0 * 8.1)),    new Point((int)(width / 30.0 * 10.36), (int)(height / 20.0 * 8.85)),    new Point((int)(width / 30.0 * 11), (int)(height / 20.0 * 9.1)),    new Point((int)(width / 30.0 * 10.34), (int)(height / 20.0 * 9.25)),    new Point((int)(width / 30.0 * 10.3), (int)(height / 20.0 * 9.95)),    new Point((int)(width / 30.0 * 9.9), (int)(height / 20.0 * 9.3))   };  } }}

希望本文所述对大家的C#程序设计有所帮助。

上一篇：C#使用加边法计算行列式的值

下一篇：C#实现将一个矩阵分解为对称矩阵与反称矩阵之和的方法