JS 密码强度校验的正则表达式(简单且好用)

2020-01-20 22:02:51

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来源：转载

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最近一直在做通行证项目，里面的注册模块中输入密码需要显示密码强度（低中高）。今天就把做的效果给大家分享下，代码没有网上搜索的那么复杂，能够满足一般的需求。

html 代码如下：

<!DOCTYPE HTML><html lang="en"><head>  <meta charset="utf-8"/>  <title>密码强度</title>  <style type="text/css">  #passStrength{height:6px;width:120px;border:1px solid #ccc;padding:2px;}  .strengthLv1{background:red;height:6px;width:40px;}  .strengthLv2{background:orange;height:6px;width:80px;}  .strengthLv3{background:green;height:6px;width:120px;}  </style></head><body>  <input type="password" name="pass" id="pass" maxlength="16"/>  <div class="pass-wrap">    <em>密码强度：</em>    <div id="passStrength"></div>  </div></body></html><script type="text/javascript" src="js/passwordStrength.js"></script><script type="text/javascript">new PasswordStrength('pass','passStrength');</script>

js 代码如下：

function PasswordStrength(passwordID,strengthID){  this.init(strengthID);  var _this = this;  document.getElementById(passwordID).onkeyup = function(){    _this.checkStrength(this.value);  }};PasswordStrength.prototype.init = function(strengthID){  var id = document.getElementById(strengthID);  var div = document.createElement('div');  var strong = document.createElement('strong');  this.oStrength = id.appendChild(div);  this.oStrengthTxt = id.parentNode.appendChild(strong);};PasswordStrength.prototype.checkStrength = function (val){  var aLvTxt = ['','低','中','高'];  var lv = 0;  if(val.match(/[a-z]/g)){lv++;}  if(val.match(/[0-9]/g)){lv++;}  if(val.match(/(.[^a-z0-9])/g)){lv++;}  if(val.length < 6){lv=0;}  if(lv > 3){lv=3;}  this.oStrength.className = 'strengthLv' + lv;  this.oStrengthTxt.innerHTML = aLvTxt[lv];};

效果图：