python 递归遍历文件夹,并打印满足条件的文件路径实例

#!/user/bin/env python# -*- coding:utf-8 -*-#grep -rl "python" D:/devtools/workspace/python/aaaimport osdef init(func): def wrapper(*args,**kwargs):  res=func(*args,**kwargs)  res.send(None)  return res return wrapper@initdef search(target): '找到文件的绝对路径' while True:  dir_name=yield  g=os.walk(dir_name)  for i in g:   for j in i[-1]:    file_path="%s//%s"%(i[0],j)    target.send(file_path)@initdef get_file_handle(target): '获取文件句柄' while True:  file_path=yield  with open(file_path) as f:   target.send((file_path,f))@initdef cat_file(target): '读取文件' while True:  file_path,f=yield  for line in f:   target.send((file_path,line))@initdef printer(pattern): '打印满足过滤条件的文件' s=set() while True:  file_path,line=yield  if pattern in line:   if file_path not in s:    print(file_path)   s.add(file_path)g=search(get_file_handle(cat_file(printer("python"))))g.send("D://devtools//workspace//python//aaa")