本文实例讲述了Python实现PS滤镜的旋转模糊功能。分享给大家供大家参考,具体如下:
这里用 Python 实现 PS 滤镜中的旋转模糊,具体的算法原理和效果可以参考附录相关介绍。Python代码如下:
from skimage import img_as_floatimport matplotlib.pyplot as pltfrom skimage import ioimport numpy as npimport numpy.matlibfile_name='D:/Visual Effects/PS Algorithm/4.jpg'img=io.imread(file_name)img = img_as_float(img)img_out = img.copy()row, col, channel = img.shapexx = np.arange (col)yy = np.arange (row)x_mask = numpy.matlib.repmat (xx, row, 1)y_mask = numpy.matlib.repmat (yy, col, 1)y_mask = np.transpose(y_mask)center_y = (row -1) / 2.0center_x = (col -1) / 2.0R = np.sqrt((x_mask - center_x) **2 + (y_mask - center_y) ** 2)angle = np.arctan2(y_mask - center_y , x_mask - center_x)Num = 20arr = ( np.arange(Num) + 1 ) / 100.0for i in range (row): for j in range (col): T_angle = angle[i, j] + arr new_x = R[i, j] * np.cos(T_angle) + center_x new_y = R[i, j] * np.sin(T_angle) + center_y int_x = new_x.astype(int) int_y = new_y.astype(int) int_x[int_x > col-1] = col - 1 int_x[int_x < 0] = 0 int_y[int_y < 0] = 0 int_y[int_y > row -1] = row -1 img_out[i,j,0] = img[int_y, int_x, 0].sum()/Num img_out[i,j,1] = img[int_y, int_x, 1].sum()/Num img_out[i,j,2] = img[int_y, int_x, 2].sum()/Numplt.figure(1)plt.imshow(img)plt.axis('off')plt.figure(2)plt.imshow(img_out)plt.axis('off')plt.show()
附:PS 滤镜——旋转模糊
这里给出灰度图像的模糊算法,彩色图像只要分别对三个通道做模糊即可。
%% spin blur% 旋转模糊clc;clear all;close all;I=imread('4.jpg');I=double(I);% % % I_new=I;% % % for kk=1:3% % % I_new(:,:,kk)=Spin_blur_Fun(I(:,:,kk), 30, 30);% % % end% % % imshow(I_new/255)Image=I;Image=0.2989 * I(:,:,1) + 0.5870 * I(:,:,2) + 0.1140 * I(:,:,3);[row, col]=size(Image);Image_new=Image;Center_X=(col+1)/2;Center_Y=(row+1)/2;validPoint=1;angle=5;radian=angle*pi/180;radian2=radian*radian;Num=30;Num2=Num*Num;for i=1:row for j=1:col validPoint=1; x0=j-Center_X; y0=Center_Y-i; x1=x0; y1=y0; Sum_Pixel=Image(i,j); for k=1:Num x0=x1; y0=y1; %%% 逆时针 % x1=x0-radian*y0/Num-radian2*x0/Num2; % y1=y0+radian*x0/Num-radian2*y0/Num2; %%% 顺时针 x1=x0+radian*y0/Num-radian2*x0/Num2; y1=y0-radian*x0/Num-radian2*y0/Num2; x=floor(x1+Center_X); y=floor(Center_Y-y1); if(x>1 && x<col && y>1 && y<row) validPoint=validPoint+1; Sum_Pixel=Sum_Pixel+Image(y,x); end end Image_new(i,j)=Sum_Pixel/validPoint; endend imshow(Image_new/255);
原图
效果图
效果图
希望本文所述对大家Python程序设计有所帮助。
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