详解pyqt5 动画在QThread线程中无法运行问题

2020-01-04 15:11:41

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自己做了一个tcp工具，在学习动画的时候踩了坑，需求是根据上线变绿色，离线变灰色，如果连接断开了，则变为灰色

问题现象：

pyqt5,QThread,线程,QThread线程,动画

可以看到点击“连接”，“离线”的时候动画是正常的，但是当tcp超时断开后，虽然离线按钮变为连接了，却没有执行离线动画

关键源代码如下

class BSJTcpThread(QtCore.QThread):  recv_signal = QtCore.pyqtSignal(str)  send_signal = QtCore.pyqtSignal(str)  def __init__(self, socketcp, onBtn, heartcheck, senBtn, scene):    super().__init__()    self.s = socketcp    self.yqtool = Bianlifunction()    self.onBtn = onBtn    self.heartcheck = heartcheck    self.sendBtn = senBtn    self.scene1 = scene  def run(self):    """线程"""    global stopsingle    stopsingle = 0    while 1:      btcpreceive = self.s.recv(1024)      tcpreceive1 = str(binascii.b2a_hex(btcpreceive), encoding="utf-8")      tcpreceive = ""      i = 0      while i < len(tcpreceive1) - 1: # 十六进制数据处理,两个字节隔开        if i == len(tcpreceive1) - 2:          tcpreceive += tcpreceive1[i:i + 2]          i += 2        else:          tcpreceive += tcpreceive1[i:i + 2] + " "          i += 2      if tcpreceive == "":        stopsingle = 1        self.s.shutdown(2)        self.s.close()        self.onBtn.setText("连接")        self.scene1.offlineCol.start() # 启动离线动画        self.heartcheck.setChecked(False)        self.heartcheck.setVisible(False)        self.sendBtn.setDisabled(True)      else:        self.recv_signal.emit(tcpreceive)      if stopsingle == 1:        break

然后再启动线程

      self.tcpth = BSJTcpThread(self.s, self.onBtn, self.heartcheck, self.sendBtn, self.scene)      self.tcpth.recv_signal.connect(self.fillrecvmsg)      self.tcpth.send_signal.connect(self.fillsendmsg)      self.tcpth.start()

问题点：

经过谷爹搜索，终于找到了问题原因详见https://stackoverflow.com/questions/44328750/pyqt-qgraphicscene-move-item-in-background-thread

大致原因就是QGraphics Scene 不是一个安全的线程对象，我们不能直接在线程中去改变主程序的状态，我们必须通过信号的方式去更新QGraphics

解决方法：

首先，我们编辑一个信号方法

  def threadAnimate(self, message):    if message == "1":      self.scene.offlineCol.start()

然后添加相关信号槽

self.tcpth = BSJTcpThread(self.s, self.onBtn, self.heartcheck, self.sendBtn)      self.tcpth.recv_signal.connect(self.fillrecvmsg)      self.tcpth.send_signal.connect(self.fillsendmsg)      self.tcpth.animate_signal.connect(self.threadAnimate) # 添加一个动画信号      self.tcpth.start()

在线程中发出离线动画的信号

class BSJTcpThread(QtCore.QThread):  recv_signal = QtCore.pyqtSignal(str)  send_signal = QtCore.pyqtSignal(str)  animate_signal = QtCore.pyqtSignal(str)  def __init__(self, socketcp, onBtn, heartcheck, senBtn):    super().__init__()    self.s = socketcp    self.yqtool = Bianlifunction()    self.onBtn = onBtn    self.heartcheck = heartcheck    self.sendBtn = senBtn  def run(self):    """线程"""    global stopsingle    stopsingle = 0    while 1:      btcpreceive = self.s.recv(1024)      tcpreceive1 = str(binascii.b2a_hex(btcpreceive), encoding="utf-8")      tcpreceive = ""      i = 0      while i < len(tcpreceive1) - 1: # 十六进制数据处理,两个字节隔开        if i == len(tcpreceive1) - 2:          tcpreceive += tcpreceive1[i:i + 2]          i += 2        else:          tcpreceive += tcpreceive1[i:i + 2] + " "          i += 2      if tcpreceive == "":        stopsingle = 1        self.s.shutdown(2)        self.s.close()        self.onBtn.setText("连接")        self.animate_signal.emit("1")        self.heartcheck.setChecked(False)        self.heartcheck.setVisible(False)        self.sendBtn.setDisabled(True)      else:        self.recv_signal.emit(tcpreceive)      if stopsingle == 1:        break

然后就可以了，这个和QThread多线程收发消息原理一样

pyqt5,QThread,线程,QThread线程,动画