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python3 flask实现文件上传功能

2020-01-04 14:41:54
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本文实例为大家分享了python3-flask文件上传操作的具体代码,供大家参考,具体内容如下

# -*- coding: utf-8 -*-import osimport uuidimport platformfrom flask import Flask,request,redirect,url_forfrom werkzeug.utils import secure_filenameif platform.system() == "Windows":  slash = '//'else:  platform.system()=="Linux"  slash = '/'UPLOAD_FOLDER = 'upload'ALLOW_EXTENSIONS = set(['html', 'htm', 'doc', 'docx', 'mht', 'pdf'])app = Flask(__name__)app.config['UPLOAD_FOLDER'] = UPLOAD_FOLDER#判断文件夹是否存在,如果不存在则创建if not os.path.exists(UPLOAD_FOLDER):  os.makedirs(UPLOAD_FOLDER)else:  pass# 判断文件后缀是否在列表中def allowed_file(filename):  return '.' in filename and /      filename.rsplit('.', 1)[1] in ALLOW_EXTENSIONS@app.route('/',methods=['GET','POST'])def upload_file():  if request.method =='POST':    #获取post过来的文件名称,从name=file参数中获取    file = request.files['file']    if file and allowed_file(file.filename):      # secure_filename方法会去掉文件名中的中文      filename = secure_filename(file.filename)      #因为上次的文件可能有重名,因此使用uuid保存文件      file_name = str(uuid.uuid4()) + '.' + filename.rsplit('.', 1)[1]      file.save(os.path.join(app.config['UPLOAD_FOLDER'],file_name))      base_path = os.getcwd()      file_path = base_path + slash + app.config['UPLOAD_FOLDER'] + slash + file_name      print(file_path)      return redirect(url_for('upload_file',filename = file_name))  return '''  <!doctype html>  <title>Upload new File</title>  <h1>Upload new File</h1>  <form action="" method=post enctype=multipart/form-data>   <p><input type=file name=file>     <input type=submit value=Upload>  </form>  '''if __name__ == "__main__":  app.run(host='0.0.0.0',port=5000)

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