python 找出list中最大或者最小几个数的索引方法

nums = [1,8,2,23,7,-4,18,23,24,37,2]result = map(nums.index, heapq.nlargest(3, nums))temp=[]Inf = 0for i in range(3):  temp.append(nums.index(max(nums)))  nums[nums.index(max(nums))]=Infresult.sort()temp.sort()print(result)print(temp)

[3, 8, 9][3, 8, 9]

nums = [1,8,2,23,7,-4,18,23,23,37,2]

[3, 3, 9][3, 7, 9]