python利用插值法对折线进行平滑曲线处理

import matplotlib.pyplot as pltimport numpy as npfrom scipy import interpolate#设置距离x =np.array([0, 1, 1.5, 2, 2.5, 3, 3.5, 4, 4.5, 5, 5.5, 6, 6.5, 70, 8, 9,10])#设置相似度y =np.array([0.8579087793827057, 0.8079087793827057, 0.7679087793827057, 0.679087793827057, 0.5579087793827057, 0.4579087793827057, 0.3079087793827057, 0.3009087793827057, 0.2579087793827057, 0.2009087793827057, 0.1999087793827057, 0.1579087793827057, 0.0099087793827057, 0.0079087793827057, 0.0069087793827057, 0.0019087793827057, 0.0000087793827057])#插值法之后的x轴值，表示从0到10间距为0.5的200个数xnew =np.arange(0,10,0.1)#实现函数func = interpolate.interp1d(x,y,kind='cubic')#利用xnew和func函数生成ynew,xnew数量等于ynew数量ynew = func(xnew)# 原始折线plt.plot(x, y, "r", linewidth=1)#平滑处理后曲线plt.plot(xnew,ynew)#设置x,y轴代表意思plt.xlabel("The distance between POI and user(km)")plt.ylabel("probability")#设置标题plt.title("The content similarity of different distance")#设置x,y轴的坐标范围plt.xlim(0,10,8)plt.ylim(0,1)plt.show()