Python3实现的简单三级菜单功能示例

#!/usr/bin/env python3# Author:Robert# --*-- coding: utf-8 --*--data = {  "北京":{    "东城区":{      "安定门":["国子监大街","孔庙","钟楼"],      "建国门":["Jinbaojie","长安街","西街"],      "朝阳门":["东四南大街","朝阳门内大街","孚王府"]      },    "朝阳区":{      "和平街":["胜古庄社区","樱花社区","和平东街社区"],      "八里庄":["慈寿寺塔","定慧寺"],      "三里屯":["798艺术区","北京工人体育馆"]    },    "海淀":{}  },  '山东':{    "德州":{},    "青岛":{},    "济南":{}  },  '广东':{    "东莞":{},    "常熟":{},    "佛山":{}  }}exit_flag = Falsewhile not exit_flag:  for i in data:    print(i)  choice = input("选择进入-->:")  if choice in data:    while not exit_flag:      for i2 in data[choice]:        print("/t",i2)      choice2 = input("选择进入2-->:")      if choice2 in data[choice]:        while not exit_flag:          for i3 in data[choice][choice2]:            print("/t/t",i3)          choice3 = input("选择进入3-->:")          if choice3 in data[choice][choice2]:            for i4 in data[choice][choice2][choice3]:              print("/t/t",i4)            choice4 = input("最后一层，按b返回-->:")            if choice4 == "b":              pass            elif choice4 == "q":              exit_flag = True          if choice3 == "b":            break          elif choice4 == "q":            exit_flag = True      if choice2 == "b":        break      elif choice4 == "q":        exit_flag = True