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使用python编写脚本获取手机当前应用apk的信息

2019-11-25 18:18:56
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前提是已设置ANDROID_HOME环境变量,使用aapt工具获取apk的信息,保存至脚本所在目录下的PackageInfo.txt文件中:

import os import tempfile import re tempFile = tempfile.gettempdir() def get_aapt(): if "ANDROID_HOME" in os.environ: rootDir = os.path.join(os.environ["ANDROID_HOME"], "build-tools") for path, subdir, files in os.walk(rootDir): if "aapt.exe" in files: return os.path.join(path, "aapt.exe") else: return "ANDROID_HOME not exist" def get_current_package_name(): pattern = re.compile(r"[a-zA-Z0-9/.]+/.[a-zA-Z0-9/.]+") os.popen("adb wait-for-device") out = os.popen("adb shell dumpsys input | findstr FocusedApplication").read() package_name = pattern.findall(out)[0].split("/")[0] return package_name def get_match_apk(package_name): list = [] for packages in os.popen("adb shell pm list packages -f " + package_name).readlines(): list.append(packages.split(":")[-1].split("=")[0]) apk_name = list[0].split("/")[-1] os.popen("adb pull " + list[0] + " " + tempFile) return tempFile + "//" + apk_name if __name__ == "__main__": os.popen(get_aapt() + / " dump badging " + / get_match_apk(get_current_package_name()) + / " > PackageInfo.txt") os.popen("del " + tempFile + "//*.apk")
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