Python实现随机生成有效手机号码及身份证功能示例

2019-11-25 16:07:31

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本文实例讲述了Python实现随机生成有效手机号码及身份证功能。分享给大家供大家参考，具体如下：

中国那么大，人那么多，几乎人手一部手机。手机号码已经作为各大互联网站的注册账户。同样，身份证更是如此。以下是生成有效手机号码和身份证号。

完整代码如下：

import osimport randomimport datetimeBASE_DIR = os.path.dirname(os.path.dirname(__file__))DC_PATH = BASE_DIR + "districtcode.txt"# 随机生成手机号码def createPhone(): prelist=["130","131","132","133","134","135","136","137","138","139","147","150","151","152","153","155","156","157","158","159","186","187","188"] return random.choice(prelist)+"".join(random.choice("0123456789") for i in range(8))# 随机生成身份证号def getdistrictcode():  with open(DC_PATH) as file:   data = file.read()   districtlist = data.split('/n')  for node in districtlist:  #print node   if node[10:11] != ' ':    state = node[10:].strip()   if node[10:11]==' 'and node[12:13]!=' ':    city = node[12:].strip()   if node[10:11] == ' 'and node[12:13]==' ':    district = node[14:].strip()    code = node[0:6]    codelist.append({"state":state,"city":city,"district":district,"code":code})def gennerator():  global codelist  codelist = []  if not codelist:  getdistrictcode() id = codelist[random.randint(0,len(codelist))]['code'] #地区项  id = id + str(random.randint(1930,2013)) #年份项  da = datetime.date.today()+datetime.timedelta(days=random.randint(1,366)) #月份和日期项  id = id + da.strftime('%m%d')  id = id+ str(random.randint(100,300))#，顺序号简单处理  i = 0 count = 0 weight = [7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2] #权重项  checkcode ={'0':'1','1':'0','2':'X','3':'9','4':'8','5':'7','6':'6','7':'5','8':'5','9':'3','10':'2'} #校验码映射  for i in range(0,len(id)):   count = count +int(id[i])*weight[i]   id = id + checkcode[str(count%11)] #算出校验码   return idprint createPhone()print gennerator()

运行结果如下：