javascript实现跳转菜单的具体方法

2019-11-20 22:33:51

字体：大中小

来源：转载

供稿：网友

传统

这里要做的是，省略Go There按钮，选择菜单项后，直接跳转。

Html代码

复制代码代码如下:

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">  
<html xmlns="http://www.w3.org/1999/xhtml">  
<head>  
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />  
<title>转移菜单</title>  
<script type="text/javascript" src="转移菜单.js"></script>  
</head>  
<body>  
<form>  
  <select id="newLocation">  
    <option selected="selected" value="">Select a topic</option>  
    <option value="topic1.html">topic1</option>  
    <option value="topic2.html">topic2</option>  
    <option value="topic3.html">topic3</option>  
    <option value="topic4.html">topic4</option>  
    <option value="topic5.html">topic5</option>  
  </select>  
  <!--当浏览器不支持javascript或者禁用脚本运行时被调用-->  
 <noscript>  
    <input type="submit" value="Go There!"/>  
 </noscript>  
</form>  
</body>  
</html>  

Javascript脚本

复制代码代码如下:

window.onload=initForm;  
//防止页面缓存，无法触发onload   
window.onunload=function(){}  
    function initForm(){  
        document.getElementById("newLocation").selectIndex=0;  
        document.getElementById("newLocation").onchange=jumpPage;  
        }  
    function jumpPage(){  
        var newLoc=document.getElementById("newLocation");  
        var newPage=newLoc.options[newLoc.selectedIndex].value;  
        if (newPage!=""){  
            window.location=newPage;  
            }  
        }  