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简单实用的反馈表单无刷新提交带验证

2019-11-20 21:40:57
字体:
来源:转载
供稿:网友
js文件可以查看源码

XML/HTML Code
复制代码 代码如下:

<div id="preview"></div>
<div id="formbox">
<form name="form" id="form" action="submit.php" method="post">
<ul id="ngothastyle3" >
<li>
<label>Name</label>
<input type="text" name="name" class="" maxlength="40" />
</li>
<li>
<label>Email</label>
<input type="text" name="email" class="" maxlength="100" />
</li>
<li>
<label>Message</label>
<textarea name="message" rows="5" cols="45" class=""></textarea>
</li>
<li>
<label> </label>
<input type="submit" value="Submit">
</li>
</ul>
</form>
</div>

JavaScript Code
复制代码 代码如下:

<script type="text/javascript">
$('document').ready(function(){

$('#form').validate({
rules:{
"name":{
required:true,
maxlength:40
},

"email":{
required:true,
email:true,
maxlength:100
},

"message":{
required:true
}},

messages:{
"name":{
required:"This field is required"
},

"email":{
required:"This field is required",
email:"Please enter a valid email address"
},

"message":{
required:"This field is required"
}},

submitHandler: function(form){
$(form).ajaxSubmit({
target: '#preview',
success: function() {
$('#formbox').slideUp('fast');
}
});

}

})

});
</script>
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