Extjs grid添加一个图片状态或者按钮的方法

renderer:function(value){
if(value==0){
return "<img src='images/icons/cancel.png'>";
}else if(value==1){
return "<img src='images/icons/accept.png'>";
}
return value;
}

<img style="cursor:pointer;" onclick="updateRecord(/''+sn+"@"+ss+"@"+record.get("standardId")+'/');" src=/'${ctx}/img/edit.png/' alt=/'明细维护/' title=/'明细维护/'>'

listeners: {
cellClick: viewDoc
}

function viewDoc(grid, rowIdx, colIdx, e) {
var action = e.getTarget().value;

}

{header:'合格证',sortable:false,width:80,align:'center',scope:this,

xtype:

'actioncolumn',
items : [{
icon : '${ctx}/img/details.png',
tooltip : '显示合格证',
handler : function(grid, rowIndex, colIndex) {
var record = grid.getStore().getAt(rowIndex);
//。。。
}
]}