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60行js代码实现俄罗斯方块

2019-11-20 12:48:54
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这是我之前网上看到的,很牛逼的一位大神写的,一直膜拜中

<!doctype html><html><head></head><body><div id="box" style="width:252px;font:25px/25px 宋体;background:#000;color:#9f9;border:#999 20px ridge;text-shadow:2px 3px 1px #0f0;"></div><script>var map=eval("["+Array(23).join("0x801,")+"0xfff]");var tatris=[[0x6600],[0x2222,0xf00],[0xc600,0x2640],[0x6c00,0x4620],[0x4460,0x2e0,0x6220,0x740],[0x2260,0xe20,0x6440,0x4700],[0x2620,0x720,0x2320,0x2700]];var keycom={"38":"rotate(1)","40":"down()","37":"move(2,1)","39":"move(0.5,-1)"};var dia, pos, bak, run;function start(){  dia=tatris[~~(Math.random()*7)];  bak=pos={fk:[],y:0,x:4,s:~~(Math.random()*4)};  rotate(0);}function over(){  document.onkeydown=null;  clearInterval(run);  alert("GAME OVER");}function update(t){  bak={fk:pos.fk.slice(0),y:pos.y,x:pos.x,s:pos.s};  if(t) return;  for(var i=0,a2=""; i<22; i++)    a2+=map[i].toString(2).slice(1,-1)+"<br/>";  for(var i=0,n; i<4; i++)    if(/([^0]+)/.test(bak.fk[i].toString(2).replace(/1/g,"/u25a1")))      a2=a2.substr(0,n=(bak.y+i+1)*15-RegExp.$_.length-4)+RegExp.$1+a2.slice(n+RegExp.$1.length);  document.getElementById("box").innerHTML=a2.replace(/1/g,"/u25a0").replace(/0/g,"/u3000");}function is(){  for(var i=0; i<4; i++)    if((pos.fk[i]&map[pos.y+i])!=0) return pos=bak;}function rotate(r){  var f=dia[pos.s=(pos.s+r)%dia.length];  for(var i=0; i<4; i++)    pos.fk[i]=(f>>(12-i*4)&15)<<pos.x;  update(is());}function down(){  ++pos.y;  if(is()){    for(var i=0; i<4 && pos.y+i<22; i++)      if((map[pos.y+i]|=pos.fk[i])==0xfff)        map.splice(pos.y+i,1), map.unshift(0x801);    if(map[1]!=0x801) return over();    start();  }  update();}function move(t,k){  pos.x+=k;  for(var i=0; i<4; i++)    pos.fk[i]*=t;  update(is());}document.onkeydown=function(e){  eval(keycom[(e?e:event).keyCode]);};start();run=setInterval("down()",400);</script></body></html>

以上所述就是本文的全部内容,希望大家能够喜欢。

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