本文实例讲述了javascript自定义右键弹出菜单实现方法。分享给大家供大家参考。具体实现方法如下:
<head runat="server"><title>无标题页</title><script type="text/javascript">var oPopup = window.createPopup();function PopMenu(id){ var oPopBody = oPopup.document.body; oPopBody.style.backgroundColor = "buttonface"; oPopBody.style.border = "solid black 1px"; var TableBegin="<table style=/"border: 0; width: 100%; font-size: 12px;/" cellpadding=/"0/" cellspacing=/"0/">"; var Tr1="<tr><td valign=/"middle/" style=/"height: 20px;/" onmousemove=/"this.bgColor='highlight';this.style.color='highlighttext'/" onmouseout=/"this.bgColor='';this.style.color=''/" onclick=/"parent.window.open('/news/view.asp?id="+id+"');/">查看新闻</td></tr>"; var TrBr1="<tr><td style=/"background-color: ThreeDShadow; height: 1px;/"></td></tr>"; var Tr2="<tr><td valign=/"middle/" style=/"height: 20px;cursor:hand;/" onmousemove=/"this.bgColor='highlight';this.style.color='highlighttext'/" onmouseout=/"this.bgColor='';this.style.color=''/" onclick=/"parent.document.frames['main'].location='divdiv.aspx?id="+id+";'/">查看新闻</td></tr>"; var TableEnd="</table>"; oPopBody.innerHTML =TableBegin+Tr1+TrBr1+Tr2+TableEnd; oPopup.show(event.x, event.y, 90, 41, document.body); return false;}</script></head><body> <form id="form1" runat="server"> <div> <a href='javascript:void(0);' oncontextmenu='PopMenu(1);return false;'> <img alt="" src='1.gif' style="border:0;width:150px;height:110px; cursor:hand"/> <br/> </a> <iframe name="main" frameborder="0" width="100%" scrolling="auto" height="100%"> </iframe> </div> </form></body></html>
希望本文所述对大家的javascript程序设计有所帮助。
新闻热点
疑难解答