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JavaScript使用RegExp进行正则匹配的方法

2019-11-20 12:03:49
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本文实例讲述了JavaScript使用RegExp进行正则匹配的方法。分享给大家供大家参考。具体实现方法如下:

<script type="text/javascript">  var matchedTimes = 0;  //Match one d followed by one or more b's followed by one d  //Remember matched b's and the following d  //Ignore case  myRe  = new RegExp("d(b+)(d)", "ig");  // 等价于 myReg = /d(b+)(d)/ig;  myArray = myRe.exec("ecDBDsdbbdz"); // ecdbBdbsdbbdz  console.log("Regular Expression String: " + myRe.source);  console.log("Is global? " + myRe.global);  console.log("Ignore case? " + myRe.ignoreCase);  console.log("Is mulitiline? " + myRe.multiline);  console.log("------------------------------------------------");  logInfo(myArray, myRe);  myArray = myRe.exec("ecDBDsdbbdz");  logInfo(myArray, myRe);  function logInfo(myArray, myRe) {    matchedTimes++;    console.log("This is " + matchedTimes + " times match");    console.log("Original String: " + myArray.input);    console.log("Match Result Array: [" + myArray + "]");    console.log("The 0-based index of the match in the string: " + myArray.index);    console.log("The last matched characters: " + myArray[0]);    console.log("The parenthesized substring matches [1]: " + myArray[1]);    console.log("The parenthesized substring matches [2]: " + myArray[2]);    console.log("The index at which to start the next match: " + myRe.lastIndex);    console.log("-----------------------------------------------");  }  myRe2 = /^/w+(/d*)$/ig  console.log("myRe2: " + myRe2.source);  //console.log("myRe2 matches abc1? " + myRe2.test("abc1"));  // 加上这行跑跑看结果,因为是global匹配,所以lastIndex会改变,  //所以后面的myRe2.test("abc")当然就是false  console.log("myRe2 matches abc? " + myRe2.test("abc"));</script>

希望本文所述对大家的javascript程序设计有所帮助。

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