jquery获取css的color值返回RGB的方法

a, a:link, a:visited { color:#4188FB; }a:active, a:focus, a:hover { color:#FFCC00; }

var link_col = $("a:link").css("color");alert(link_col); // returns rgb(65, 136, 251)

var rgbString = "rgb(0, 70, 255)"; // get this in whatever way.var parts = rgbString.match(/^rgb/((/d+),/s*(/d+),/s*(/d+)/)$/);// parts now should be ["rgb(0, 70, 255", "0", "70", "255"]delete (parts[0]);for (var i = 1; i <= 3; ++i) {parts[i] = parseInt(parts[i]).toString(16);if (parts[i].length == 1) parts[i] = '0' + parts[i];}var hexString = parts.join(''); // "0070ff"

function rgb2hex(rgb) {rgb = rgb.match(/^rgb/((/d+),/s*(/d+),/s*(/d+)/)$/);function hex(x) {return ("0" + parseInt(x).toString(16)).slice(-2);}return "#" + hex(rgb[1]) + hex(rgb[2]) + hex(rgb[3]);}