jQuery实现动态给table赋值的方法示例

2019-11-19 16:10:55

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本文实例讲述了jQuery实现动态给table赋值的方法。分享给大家供大家参考，具体如下：

html

请忽视各种class，因为前端用的是layui

<table class="layui-table" lay-skin="line" id="datas">  <colgroup>    <col width="150">    <col width="200">    <col>  </colgroup>  <thead>  <tr>    <th>昵称</th>    <th>加入时间</th>    <th>签名</th>  </tr>  </thead>  <tbody>  <tr id="template">    <td id="id"></td>    <td id="url"></td>    <td id="title"></td>  </tr>  </tbody></table>

js代码

<script>  var data = [{      "id": 1,      "url": "http://www.jqcool.net",      "switch": 1,      "order": 1,      "pid": 0,      "title": "Online Program knowledge share and study platform"    },      {        "id": 2,        "url": "http://www.baidu.com",        "switch": 0,        "order": 2,        "pid": 2,        "title": "这是测试的数数据这是测试的数数据"      },      {        "id": 3,        "url": "http://www.taobao.com",        "switch": 0,        "order": 3,        "pid": 2,        "title": "淘宝购物"      },      {        "id": 4,        "url": "http://www.jqcool.net1",        "switch": 1,        "order": 4,        "pid": 2,        "title": "Online Program knowledge share and study platform2"      },      {        "id": 5,        "url": "http://www.baidu.com1",        "switch": 0,        "order": 5,        "pid": 2,        "title": "这是测试的数数据2"      },      {        "id": 6,        "url": "http://www.taobao.com1",        "switch": 1,        "order": 6,        "pid": 0,        "title": "淘宝购物2"      }];  $.each(data, function (i, n) {    var row = $("#template").clone();    row.find("#id").text(n.id);    row.find("#url").text(n.url);    row.find("#title").text(n.title);    row.appendTo("#datas");//添加到模板的容器中  });</script>

效果