JavaScript 数组去重并统计重复元素出现的次数实例

var arr = [1, 2, 3, 1, 2, 4];  function arrayCnt(arr) {  var newArr = [];  for(var i = 0; i < arr.length; i++) {   if(newArr.indexOf(arr[i]) == -1) {   newArr.push(arr[i])   }  }  var newarr2 = new Array(newArr.length);  for(var t = 0; t < newarr2.length; t++) {   newarr2[t] = 0;  }  for(var p = 0; p < newArr.length; p++) {   for(var j = 0; j < arr.length; j++) {   if(newArr[p] == arr[j]) {    newarr2[p]++;   }   }  }  for(var m = 0; m < newArr.length; m++) {   console.log(newArr[m] + "重复的次数为：" + newarr2[m]);  }  }  arrayCnt(arr);

var arr = [1, 2, 3, 1, 2, 4];  function arrayCnt(arr) {  var newArr = [];  //使用set进行数组去重  newArr = [...new Set(arr)];  var newarr2 = new Array(newArr.length);  for(var t = 0; t < newarr2.length; t++) {   newarr2[t] = 0;  }  for(var p = 0; p < newArr.length; p++) {   for(var j = 0; j < arr.length; j++) {   if(newArr[p] == arr[j]) {    newarr2[p]++;   }   }  }  for(var m = 0; m < newArr.length; m++) {   console.log(newArr[m] + "重复的次数为：" + newarr2[m]);  }  }  arrayCnt(arr);