js中Array对象的常用遍历方法详解

2019-11-19 12:16:39

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1.forEach(),遍历数组的每个元素

  let arrFor = ['muzi','digbig','muzidigbig','lucky']  //forEach(),遍历数组的每个元素  arrFor.forEach((item,index) => {    console.log(`${index}---${item}`)  })

2.map(参数为回调函数)函数，遍历数组每个元素，并回调操作，需要返回值，返回值组成新数组，原数组不变；

  let arr = [{id:1,name:'muzi'},{id:2,name:'digbig'},{id:3,name:'muzidigbig'},{id:4,name:'lucky'}]  const arrMap = arr.map((item,index) => {    return {      id:item.id,      name:item.name,      sex:'男'    }  })  console.log(arrMap)

3.filter(参数为回调函数)函数：过滤通过条件的元素组成一个新数组，原数组不变；

  let arr = [{id:1,name:'muzi'},{id:2,name:'digbig'},{id:3,name:'muzidigbig'},{id:4,name:'lucky'}]  const arrFilter = arr.filter((item,index) => {    return item.id >= 2;  })  console.log(arrFilter)

4.some(参数为回调函数)函数，遍历数组中是否有符合条件的函数，返回布尔值；

  let arr = [{id:1,name:'muzi'},{id:2,name:'digbig'},{id:3,name:'muzidigbig'},{id:4,name:'lucky'}]  const arrSome = arr.some((item,index) => {    return item.id === 5  })  console.log(arrSome)

5.every(参数为回调函数)函数，遍历数组是否每个元素都符合条件，返回布尔值；

  let arr = [{id:1,name:'muzi'},{id:2,name:'digbig'},{id:3,name:'muzidigbig'},{id:4,name:'lucky'}]  const arrEvery = arr.every((item,index) => {    return item.id >= 1  })  console.log(arrEvery)

6.find()函数，数组中的每个元素都执行这个回调函数；返回第一个满足条件的元素之后的元素就不在调用；没有符合的返回undefined；并没有改变数组的原始值。

  let arr = [{id:1,name:'muzi'},{id:2,name:'digbig'},{id:3,name:'muzidigbig'},{id:4,name:'lucky'}]  const arrFind = arr.find((item,index) => {    return item.id === 1  })  console.log(arrFind)

7.reduce(),合并二维数组

  var twoArr = [['mu','zi'],['dig','big'],['lucky','jiji']];  var oneArr = twoArr.reduce(function(total,currentValue){    // console.log(total)    return total.concat(currentValue);  },[])  console.log(oneArr);//["mu", "zi", "dig", "big", "lucky", "jiji"]

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