https://leetcode.com/PRoblems/merge-two-sorted-lists/
算法思想:Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists.
连接两个排好序(假设升序,降序类似)的链表,这是一道典型的递归题。比较两个链表的第一个元素,如果l1的第一个node的值要比l2的第一个node的值小,那么新的链表的第一个node就是l1的第一个node,第二个node开始就是l1的第二个node和l2连接起来的list;反之同。
程序清单:/** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } * } */public class Solution { public ListNode mergeTwoLists(ListNode l1, ListNode l2) { if (l1 == null) { return l2; } if (l2 == null) { return l1; } if (l1.val < l2.val) { l1.next = mergeTwoLists(l1.next, l2); return l1; } else { l2.next = mergeTwoLists(l1, l2.next); return l2; } }}
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