首页 > 学院 > 开发设计 > 正文

itertools模块速查

2019-11-14 17:52:27
字体:
来源:转载
供稿:网友

学习itertools模块记住这张表就OK了

参考:http://docs.python.org/2/library/itertools.html#module-itertools 

 

Infinite Iterators:

IteratorArgumentsResultsExample
count()start, [step]start, start+step, start+2*step, ...count(10) --> 10 11 12 13 14 ...
cycle()pp0, p1, ... plast, p0, p1, ...cycle('ABCD') --> A B C D A B C D ...
repeat()elem [,n]elem, elem, elem, ... endlessly or up to n timesrepeat(10, 3) --> 10 10 10

 

Iterators terminating on the shortest input sequence:

IteratorArgumentsResultsExample
chain()p, q, ...p0, p1, ... plast, q0, q1, ...chain('ABC', 'DEF') --> A B C D E F
comPRess()data, selectors(d[0] if s[0]), (d[1] if s[1]), ...compress('ABCDEF', [1,0,1,0,1,1]) --> A C E F
dropwhile()pred, seqseq[n], seq[n+1], starting when pred failsdropwhile(lambda x: x<5, [1,4,6,4,1]) --> 6 41
groupby()iterable[, keyfunc]sub-iterators grouped by value of keyfunc(v) 
ifilter()pred, seqelements of seq where pred(elem) is trueifilter(lambda x: x%2, range(10)) --> 1 3 5 79
ifilterfalse()pred, seqelements of seq where pred(elem) is falseifilterfalse(lambda x: x%2, range(10)) --> 02 4 6 8
islice()seq, [start,] stop [, step]elements from seq[start:stop:step]islice('ABCDEFG', 2, None) --> C D E F G
imap()func, p, q, ...func(p0, q0), func(p1, q1), ...imap(pow, (2,3,10), (5,2,3)) --> 32 9 1000
starmap()func, seqfunc(*seq[0]), func(*seq[1]), ...starmap(pow, [(2,5), (3,2), (10,3)]) --> 32 91000
tee()it, nit1, it2, ... itn splits one iterator into n 
takewhile()pred, seqseq[0], seq[1], until pred failstakewhile(lambda x: x<5, [1,4,6,4,1]) --> 1 4
izip()p, q, ...(p[0], q[0]), (p[1], q[1]), ...izip('ABCD', 'xy') --> Ax By
izip_longest()p, q, ...(p[0], q[0]), (p[1], q[1]), ...izip_longest('ABCD', 'xy', fillvalue='-') -->Ax By C- D-

 

Combinatoric generators:

IteratorArgumentsResults
product()p, q, ... [repeat=1]cartesian product, equivalent to a nested for-loop
permutations()p[, r]r-length tuples, all possible orderings, no repeated elements
combinations()p, rr-length tuples, in sorted order, no repeated elements
combinations_with_replacement()p, rr-length tuples, in sorted order, with repeated elements
product('ABCD', repeat=2) AA AB AC AD BA BB BC BD CA CB CC CD DA DB DC DD
permutations('ABCD', 2) AB AC AD BA BC BD CA CB CD DA DB DC
combinations('ABCD', 2) AB AC AD BC BD CD
combinations_with_replacement('ABCD', 2) AA AB AC AD BB BC BD CC CD DD

发表评论 共有条评论
用户名: 密码:
验证码: 匿名发表