首页 > 学院 > 开发设计 > 正文

Homework #1 for MAFS 5220

2019-11-14 09:56:31
字体:
来源:转载
供稿:网友
"""Created on Sun Nov 6 16:26:56 2016@author: Stan WangAssignment_1 Delta hedging of an option"""import scipy as spimport mathimport numpy as npimport scipy.stats as ssdef d1(S0, K, r, sigma, T): return (np.log(S0/K) + (r + sigma**2 / 2) * T)/(sigma * np.sqrt(T))def d2(S0, K, r, sigma, T): return (np.log(S0/K) + (r - sigma**2 / 2) * T)/(sigma * np.sqrt(T))# the Black-Shoes option PRicedef BS_Call(S0, K, r, sigma, T): return S0 * ss.norm.cdf(d1(S0, K, r, sigma, T)) - K * np.exp(-r * T) * ss.norm.cdf(d2(S0, K, r, sigma, T))def MC_deltaHedging_Call(S # stock price ,X # strike price ,T # maturity ,sigma # volatility ,expectedReturn # the stock's expected Return ,r # riskless return rate ,numMC # number of Monte Carlo ,numsim # number of days to the maturity ): dt = T/float(numsim) drift=(r-0.5*sigma*sigma)*dt sigmasqrtdt = sigma * math.sqrt(dt) portfolio = sp.zeros([numMC],dtype=float) interest = np.exp(r*dt) # Assume that we adjust our portfolio at the beginning of the business day; for j in range(0,numMC): # At the first day #print("In the first day: ") stockPrice = S callValue01 = BS_Call(stockPrice,X,r,sigma,T) # according to BS, delta=N(d1) delta01 = ss.norm.cdf(d1(stockPrice,X,r,sigma,T)) # we long one call option, and short delta stock to hedge it. # and we put the extra money(positive or negative) # into the money account moneyAccount = delta01 * stockPrice - callValue01 print("the stock price is {}".format(stockPrice)) print("to hedge one call option, we sell {} shares of stock".format(delta01)) # From the second day to the last day for i in range(1,numsim): print("in the {} day: ".format(i+1)) # assume that the stock price is GBM e = sp.random.normal(0,1) stockPrice *= np.exp(drift + sigmasqrtdt * e) print("the stock price is {}".format(stockPrice) ) # every day the money in the money account will earn or pay # interest at the rate of r; moneyAccount *= interest # the call value and corresponding delta; callValue02 = BS_Call(stockPrice,X,r,sigma,T-i*dt) delta02 = ss.norm.cdf(d1(stockPrice,X,r,sigma,T-i*dt)) # P&L of this call option; PnL_call = callValue02 - callValue01 print("the P&L of the option is {}".format(PnL_call)) print("the new delta is {}".format(delta01)) # due to new delta, we need to buy or sell stocks at the value of # delta01 - delta02 which means buying if positive, or selling if # negative; print("the amount of stock we changed is {}".format(delta01-delta02)) # adjust the value of money account; moneyAccount +=(delta02-delta01)*stockPrice delta01 = delta02 callValue01=callValue02 # At maturity, the call value is given by terminal condition; e = sp.random.normal(0,1); stockPrice *= math.exp(drift+sigmasqrtdt * e) print("the stock price at maturity is {}".format(stockPrice)) callValue = max(stockPrice-X,0) print("the call value at maturity is {}".format(callValue)) # we can caculated the portfolio value at maturity; moneyAccount *= interest portfolio[j] = moneyAccount+callValue-delta01*stockPrice print("the portfolio at maturity is {}".format(portfolio[j])) # After numMC of Monte Cal portfolioValue =sp.mean(portfolio) return portfolioValueprint("the result from Monte Carlo for delta hedging strategy is {}".format(MC_deltaHedging_Call(100,100,1,0.1,0.1,0.05,1,360)))# Remark: we can NOT make or lose money by using the delta hedging strategy under the assumptions of Black-Sholes model.
发表评论 共有条评论
用户名: 密码:
验证码: 匿名发表