首页 > 学院 > 开发设计 > 正文

【LeetCode】461. Hamming Distance【E】【90】

2019-11-08 19:25:34
字体:
来源:转载
供稿:网友

The Hamming distance between two integers is the number of positions at which the corresponding bits are different.

Given two integers x and y, calculate the Hamming distance.

Note:0 ≤ xy < 231.

Example:

Input: x = 1, y = 4Output: 2Explanation:1   (0 0 0 1)4   (0 1 0 0)       ↑   ↑The above arrows point to positions where the corresponding bits are different.

Subscribe to see which companies asked this question.思路很简单,先转成二进制,然后计算异或,然后看一共有多少个1 就是结果了 
class Solution(object):    def hammingDistance(self, x, y):        return ((bin(x ^ y)[2:])).count('1')        """        :type x: int        :type y: int        :rtype: int        """
发表评论 共有条评论
用户名: 密码:
验证码: 匿名发表