The Hamming distance between two integers is the number of positions at which the corresponding bits are different.
Given two integers x
and y
, calculate the Hamming distance.
Note:0 ≤ x
, y
< 231.
Example:
Input: x = 1, y = 4Output: 2Explanation:1 (0 0 0 1)4 (0 1 0 0) ↑ ↑The above arrows point to positions where the corresponding bits are different.Subscribe to see which companies asked this question.思路很简单,先转成二进制,然后计算异或,然后看一共有多少个1 就是结果了class Solution(object): def hammingDistance(self, x, y): return ((bin(x ^ y)[2:])).count('1') """ :type x: int :type y: int :rtype: int """
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