C#判断字符串是否是int/double（实例）

using System.Text.RegularExpressions;/// <summary>/// 判断字符串是否是int/double/// </summary>public static bool IsIntOrDouble(string strNumber){ Regex objNotNumberPattern = new Regex("[^0-9.-]"); Regex objTwoDotPattern = new Regex("[0-9]*[.][0-9]*[.][0-9]*"); Regex objTwoMinusPattern = new Regex("[0-9]*[-][0-9]*[-][0-9]*"); const string strValidRealPattern = "^([-]|[.]|[-.]|[0-9])[0-9]*[.]*[0-9]+$"; const string strValidIntegerPattern = "^([-]|[0-9])[0-9]*$"; Regex objNumberPattern = new Regex("(" + strValidRealPattern + ")|(" + strValidIntegerPattern + ")"); return !objNotNumberPattern.IsMatch(strNumber) &&  !objTwoDotPattern.IsMatch(strNumber) &&  !objTwoMinusPattern.IsMatch(strNumber) &&  objNumberPattern.IsMatch(strNumber);}