JSP如何实现快速上传文件?文件上传是我们经常要用到的一个功能,那么现在我们就一起去看看实现JSP快速上传文件的方法,希望能给你带来帮助。
这里演示JSP不使用第三方库,实现快速上传文件的功能
1. FileUpload.java:
package FileUpload;import java.io.BufferedOutputStream;import java.io.File;import java.io.FileOutputStream;import javax.servlet.ServletInputStream;/** * *//** * @author Qch * */public class FileUpload{ ServletInputStream in=null; String fpath="C://"; public FileUpload() { fpath="C://"; in=null; } public void setInputStream(ServletInputStream in) { this.in=in; } public void setFpath(String p) { this.fpath=p; } public String getFpath() { return fpath; } public String getParameter() { String r=null; try { r=getParameter(in); } catch (Exception e) { e.printStackTrace(); } return r; } public long getFileUpload() { long r=-1; try { r=getFileUpload(in,fpath); } catch (Exception e) { e.printStackTrace(); } return r; } public String getParameter(ServletInputStream in)// 只能按顺序提取 throws Exception { int l = 0; byte[] b = new byte[1024]; l = in.readLine(b, 0, b.length);// 依次是读取属性的开始符、名称、属性值的类型、属性的值 String si = new String(b); if (si.startsWith("----------------------------")) {// 表示是从开始符开始读,否则应为刚读取文件后的一个属性,此时应少读一次 l = in.readLine(b, 0, b.length); } l = in.readLine(b, 0, b.length); l = in.readLine(b, 0, b.length); String value = new String(b, 0, l); return value; } public long getFileUpload(ServletInputStream in, String fpath)// 需要提供输入流和存储路径 throws Exception { // out.println("文件信息:"); long begin = System.currentTimeMillis();// 传送时间计时开始 int l = 0; byte[] b = new byte[1024]; l = in.readLine(b, 0, b.length); String sign = new String(b, 0, l);// eg.-----------------------------7d9dd29630a34 l = in.readLine(b, 0, b.length); String info = new String(b, 0, l);// eg.Content-Disposition:form-data; // name="file"; l = in.readLine(b, 0, b.length); // String type=new // String(b,0,l);//eg.Content-Type:application/octet-stream(程序文件) l = in.readLine(b, 0, b.length); // String nulll=new String(b,0,l);//此值应为空 int nIndex = info.toLowerCase().indexOf("filename=/""); int nLastIndex = info.toLowerCase().indexOf("/"", nIndex + 10); String filepath = info.substring(nIndex + 10, nLastIndex); int na = filepath.lastIndexOf("//"); String filename = filepath.substring(na + 1); // out.println("文件绝对路径:"+filepath+""); // out.println("文件名:"+filename+""); String path=fpath + filename; File fi = new File(path);// 建立目标文件 if (!fi.exists()&&!fi.createNewFile()) return -2; BufferedOutputStream f = new BufferedOutputStream(new FileOutputStream( fi)); while ((l = in.readLine(b, 0, b.length)) > 0) { if (l == sign.length()) { String sign1 = new String(b, 0, sign.length()); // out.println(sign1+""); if (sign1.startsWith(sign))// 比对是否文件已传完 break; } f.write(b, 0, l); f.flush(); } f.flush(); f.close(); long end = System.currentTimeMillis();// 传送时间计时结束 // out.println("上传文件用时:"+(end-begin)+"毫秒"); return end - begin; }}
2. submitFile.jsp:
<%@ page language="java" import="java.util.*" pageEncoding="GB18030"%><% String path = request.getContextPath(); String basePath = request.getScheme() + "://" + request.getServerName() + ":" + request.getServerPort() + path + "/";%>
My JSP 'submitFile.jsp' starting page
3. AnswerFile.jsp:
<%@ page language="java" import="java.util.*,java.io.*" pageEncoding="GB18030"%><% String path = request.getContextPath(); String basePath = request.getScheme() + "://" + request.getServerName() + ":" + request.getServerPort() + path + "/";%>
My JSP 'AnswerFile.jsp' starting page
"); long time = upload.getFileUpload(); out.println("文件上传完毕,总共耗时:" + time + "毫秒
"); String leixing = upload.getParameter(); out.println("文件类型:" + leixing + "
"); in.close(); %>
以上就是实现JSP快速上传文件的方法,我们用实例分析了JSP不使用第三方库实现快速上传文件的完整流程与相关技巧。
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