jquery访问servlet并返回数据到页面的方法

本文实例讲述了jquery访问servlet并返回数据到页面的方法。。具体实现方法如下：

1. servlet:AjaxServlet.java如下：
代码如下:package com.panlong.servlet; 

import java.io.IOException; 
import java.io.PrintWriter; 
import java.net.URLDecoder; 

import javax.servlet.ServletException; 
import javax.servlet.http.HttpServlet; 
import javax.servlet.http.HttpServletRequest; 
import javax.servlet.http.HttpServletResponse; 

public class AjaxServlet extends HttpServlet { 
    private static final long serialVersionUID = 1L; 
    protected void doGet(HttpServletRequest req, HttpServletResponse resp) 
            throws ServletException, IOException { 
        Integer total = (Integer) req.getSession().getAttribute("total"); 
        int temp = 0; 
        if(total == null ){ 
            temp = 1; 
        }else{ 
            temp = total.intValue() + 1; 
        } 
    req.getSession().setAttribute("total",temp); 
        try { 
            //1.取参数 
            resp.setContentType("text/html;charset=GBK"); 
            PrintWriter out = resp.getWriter(); 
            String old = req.getParameter("name"); 
            //2.检查参数是否有问题 
            //String name = new String(old.getBytes("iso8859-1"),"UTF-8"); 
            String name = URLDecoder.decode(old,"UTF-8"); 
            if("".equals(old) || old == null){ 
                out.println("用户名必须输入"); 
            }else{ 
                if("liling".equals(name)){ 
                    out.println("恭喜登录成功");