Linux查看当前登录用户并踢出用户的命令

 1、查看当前登录用户

[wilsh@lcl ~]$ whatis w w     (1) - Show who is logged on and what they are doing [wilsh@lcl ~]$ w  09:49:30 up 1 day, 17:19, 4 users, load average: 0.00, 0.00, 0.00 USER  TTY  FROM    LOGIN@ IDLE JCPU PCPU WHAT root  tty3  -    09:25 23:25 0.10s 0.08s -bash root  pts/0 192.168.105.188 09:32 9:38 0.02s 0.02s -bash root  pts/1 192.168.105.188 09:36 9:32 0.03s 0.02s -bash wilsh pts/2 192.168.105.188 09:41 0.00s 0.00s 0.00s w 

2、踢出当前在线的用户

a)pkill

[wilsh@lcl ~]$ whatis pkill pkill [pgrep]  (1) - look up or signal processes based on name and other attributes [wilsh@lcl ~]$ pkill -KILL -u wilsh #-u用来指定用户名 [wilsh@lcl ~]$ pkill -9 -u wilsh # -KILL -9都是可以的。 [wilsh@lcl ~]$ pkill -KILL -t pts/2 [wilsh@lcl ~]$ pkill -KILL -t /dev/pts/2 # 这种写法是错误的。因为在man page中明确说明，如果要使用-t参数，那么就不能带/dev/前辍。<span ><span >#在centos6.7 kernel 3.10.28中测试，发现写完整的设备名并不起作用（如/dev/pts/2）,本文是在kernel 2.6.32中写的，昨天晚上刚刚重启编译完3.10.28的内核，测试了一下又不可以了，郁闷。</span></span> 

b)skill

[wilsh@lcl ~]$ whatis skill skill    (1) - send a signal or report process status [wilsh@lcl ~]$ skill -9 -t pts/2 [wilsh@lcl ~]$ w  09:57:37 up 1 day, 17:28, 4 users, load average: 0.00, 0.00, 0.00 USER  TTY  FROM    LOGIN@ IDLE JCPU PCPU WHAT root  tty3  -    09:25 31:32 0.10s 0.08s -bash root  pts/0 192.168.105.188 09:32 17:45 0.02s 0.02s -bash root  pts/1 192.168.105.188 09:36 17:39 0.01s 0.01s -bash wilsh pts/2 192.168.105.188 09:57 0.00s 0.00s 0.00s w [wilsh@lcl ~]$ skill -9 -u wilsh 

总结

以上所述是小编给大家介绍的Linux查看当前登录用户并踢出用户的命令，希望对大家有所帮助，如果大家有任何疑问欢迎给我留言，小编会及时回复大家的！