这篇文章主要介绍了从MySQL的源码剖析Innodb buffer的命中率计算,作者结合C语言写的算法来分析innodb buffer hit Ratios,需要的朋友可以参考下
按官方手册推荐Innodb buffer Hit Ratios的计算是:
- 100-((iReads / iReadRequests)*100)
- iReads : mysql->status->Innodb_buffer_pool_reads
- iReadRequests: mysql->status->Innodb_buffer_pool_read_requests
出处: http://dev.mysql.com/doc/mysql-monitor/2.0/en/mem_graphref.html
搜”Hit Ratios”
推荐有兴趣的同学把这个页面都看一下应该也会有很大收获.
另外在hackmysql: www.hackmysql.com网站上的: mysqlsqlreport中关于buffer命中计算是:
- $ib_bp_read_ratio = sprintf "%.2f",
- ($stats{'Innodb_buffer_pool_read_requests'} ?
- 100 - ($stats{'Innodb_buffer_pool_reads'} /
- $stats{'Innodb_buffer_pool_read_requests'}) * 100 :0);
即:
- ib_bp_hit=100-(Innodb_buffer_pool_reads/Innodb_buffer_pool_read_requests)*100
另外我们知道查看Innodb Buffer Hit Ratios的地方是:
复制代码代码如下:
show engine innodb status/G;
Buffer pool hit rate : XXXX/1000;
那个XXX/1000即是buffer pool hit ratios的命中.
这样也可以从代码里看一下这个bp命中计算:
- storage/innobase/buf/buf0buf.c # void buf_print_io
- storage/innodbase/include/buf0buf.h #struct buf_block_struct
在buf0buf.c 中的buf_print_io函数中可以看到:
- void
- buf_print_io(
- …
- if (buf_pool->n_page_gets > buf_pool->n_page_gets_old) {
- fprintf(file, "Buffer pool hit rate %lu / 1000/n",
- (ulong)
- (1000 - ((1000 * (buf_pool->n_pages_read
- - buf_pool->n_pages_read_old))
- / (buf_pool->n_page_gets
- - buf_pool->n_page_gets_old))));
- } else {
- fputs("No buffer pool page gets since the last printout/n",
- file);
- }
- buf_pool->n_page_gets_old = buf_pool->n_page_gets;
- buf_pool->n_pages_read_old = buf_pool->n_pages_read;
- …
- }
结合:
storage/innobase/include/buf0buf.h中
- struct buf_block_struct{
- …
- ulint n_pages_read; /* number read operations */
- …
- ulint n_page_gets; /* number of page gets performed;
- also successful searches through
- the adaptive hash index are
- counted as page gets; this field
- is NOT protected by the buffer
- pool mutex */
- …
- ulint n_page_gets_old;/* n_page_gets when buf_print was
- last time called: used to calculate
- hit rate */
- …
- ulint n_pages_read_old;/* n_pages_read when buf_print was
- last time called */
- …
从这个来看innodb buffer hit Ratios的命中计算需要本次取的值和上次值做一个减法公式应该为
- ib_bp_hit=1000 – (t2.iReads – t1.iReads)/(t2.iReadRequest – t1.iReadRequest)*1000
t(n): 时间点 两个时间间隔最少是30秒以上,在小意义不大.
- iReads: Innodb_buffer_pool_reads
- iReadRequest: Innodb_buffer_pool_read_requests
对innodb的输出参数有兴趣的可以关注: storage/innobase/buf/Srv0srv.c 中的:
- void srv_export_innodb_status()
思考:
对于innodb_buffer_pool_read_requests, innodb_buffer_pool_reads这种累加值,当很大时进行: innodb_buffer_pool_reads/innodb_buffer_pool_read_requests 相来讲只能得到从开始到现在的命中率的表现了. 如果想得到现在近五分钟,近一分钟或是8点到9点每分钟的命中率情况,如果还是按着innodb_buffer_pool_reads/innodb_buffer_pool_read_requests 进行计算,只能得到mysqld开起累计在8点-9点的每分钟的累计平均命中情况.
所以如果想到每(五)分钟的命中情况,就需要本次取得的值和一(五)分钟前的值进行相减,然后进行运算.这样才能得到一个当下的bp命中情况.
两种方法没实质的对错的问题,但相对于源码中的那种计算方式更容让发现数据库的抖动问题.
能解决的问题:
偶而的数据库性能抖动能直观的反应出来.
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