如何通过SQL找出2个表里值不同的列的方法

SELECT *
FROM Student_1 S1
WHERE NOT EXISTS
(SELECT *
FROM Student_2 S2
WHERE S1.name = S2.name
AND S1.age = S2.age
AND S1.score = S2.score
)
UNION ALL
SELECT *
FROM STUDENT_2 S2
WHERE NOT EXISTS
(SELECT *
FROM STUDENT_1 S1
WHERE S1.name = S2.name
AND S1.age = S2.age
AND S1.score = S2.score
);

(SELECT * FROM Student_1
MINUS
SELECT * FROM Student_2)
UNION ALL
(SELECT * FROM Student_2
MINUS
SELECT * FROM Student_1)

SELECT DISTINCT name, age, score FROM (
SELECT * FROM Student_1
UNION ALL
SELECT * FROM Student_2
)GROUP BY name, age, score HAVING COUNT(*)=1 ;