通过调整表union all的顺序优化SQL

　　操作系统：Windows xp

　　数据库版本：SQL Server 2005

　　今天遇到一个SQL，过滤条件是自动生成的，因此，没法通过调整SQL的谓词达到优化的目的，只能去找SQL中的“大表”。有一个视图返回的结果集比较大，如果能调整的话，也只能调整该视图了。

　　看了一下该视图的结构，里面还套用了另一层视图，直接看最里层视图的查询SQL。

SELECT  a.dfeesum_no ,        a.oPR_amt - ISNULL(b.dec_pay, 0) - ISNULL(b.dec_corrpay, 0)        - ISNULL(b.dec_deduamt, 0) dec_amt ,        a.dec_camt - ISNULL(b.dec_pay, 0) - a.dec_comprate        * ISNULL(b.dec_deduamt, 0) dec_compamt ,        a.dec_ramt - ISNULL(b.dec_corrpay, 0) - ( a.dec_comprate - 1 )        * ISNULL(b.dec_deduamt, 0) dec_corramt ,        a.dec_qty - ISNULL(b.dec_qty, 0) - ISNULL(b.dec_deduqty, 0) opr_qty ,        ISNULL(b.dec_pay, 0) dec_pay ,        ISNULL(b.dec_corrpay, 0) dec_corrpay ,        ISNULL(b.dec_deduqty, 0) dec_deduqty ,        ISNULL(b.dec_deduamt, 0) dec_deduamt ,        ISNULL(b.dec_qty, 0) dec_qtyFROM    ctlm8686 a        LEFT JOIN ( SELECT  dfeesum_no ,                            SUM(dec_ramt) dec_pay ,                            SUM(dec_corramt) dec_corrpay ,                            SUM(dec_qty) dec_qty ,                            SUM(CASE WHEN flag_dedu = '1' THEN dec_deduamt                                     ELSE 0                                END) dec_deduamt ,                            SUM(CASE WHEN flag_dedu = '1' THEN dec_deduqty                                     ELSE 0                                END) dec_deduqty                    FROM    dfeepay_03                    GROUP BY dfeesum_no                  ) b ON a.dfeesum_no = b.dfeesum_noUNION ALLSELECT  a.dfeesum_no ,        a.dec_amt - ISNULL(b.dec_pay, 0) - ISNULL(b.dec_corrpay, 0)        - ISNULL(b.dec_deduamt, 0) dec_amt ,        a.dec_compamt - ISNULL(b.dec_pay, 0) - a.dec_comprate        * ISNULL(b.dec_deduamt, 0) dec_compamt ,        a.dec_corramt - ISNULL(b.dec_corrpay, 0) - ( a.dec_comprate - 1 )        * ISNULL(b.dec_deduamt, 0) dec_corramt ,        a.opr_qty - ISNULL(b.dec_qty, 0) - ISNULL(b.dec_deduqty, 0) opr_qty ,        ISNULL(b.dec_pay, 0) dec_pay ,        ISNULL(b.dec_corrpay, 0) dec_corrpay ,        ISNULL(b.dec_deduqty, 0) dec_deduqty ,        ISNULL(b.dec_deduamt, 0) dec_deduamt ,        ISNULL(b.dec_qty, 0) dec_qtyFROM    dfeeapp_03 a        LEFT JOIN ( SELECT  dfeesum_no ,                            SUM(dec_ramt) dec_pay ,                            SUM(dec_corramt) dec_corrpay ,                            SUM(dec_qty) dec_qty ,                            SUM(CASE WHEN flag_dedu = '1' THEN dec_deduamt                                     ELSE 0                                END) dec_deduamt ,                            SUM(CASE WHEN flag_dedu = '1' THEN dec_deduqty                                     ELSE 0                                END) dec_deduqty                    FROM    dfeepay_03                    GROUP BY dfeesum_no                  ) b ON a.dfeesum_no = b.dfeesum_no

　　返回结果集有1433891行，其中

　　SELECT COUNT(*) FROM dfeepay_03 --1103914　　SELECT COUNT(*) FROM ctlm8686 --1131586　　SELECT COUNT(*) FROM dfeeapp_03--302305

　　上述SQL脚本中，子查询是相同的，即对子查询进行了两次扫描，可以考虑先让dfeeapp_03和ctlm8686union all，再left joindfeepay_03 。同时，对于子查询，先让dfeepay_03 表先查询出flag_dedu = '1'的数据，就不用再进行case when判断了。

　　改写后的SQL如下

SELECT  a.dfeesum_no ,        a.opr_amt - ISNULL(b.dec_pay, 0) - ISNULL(b.dec_corrpay, 0)        - ISNULL(b.dec_deduamt, 0) dec_amt ,        a.dec_camt - ISNULL(b.dec_pay, 0) - a.dec_comprate        * ISNULL(b.dec_deduamt, 0) dec_compamt ,        a.dec_ramt - ISNULL(b.dec_corrpay, 0) - ( a.dec_comprate - 1 )        * ISNULL(b.dec_deduamt, 0) dec_corramt ,        a.dec_qty - ISNULL(b.dec_qty, 0) - ISNULL(b.dec_deduqty, 0) opr_qty ,        ISNULL(b.dec_pay, 0) dec_pay ,        ISNULL(b.dec_corrpay, 0) dec_corrpay ,        ISNULL(b.dec_deduqty, 0) dec_deduqty ,        ISNULL(b.dec_deduamt, 0) dec_deduamt ,        ISNULL(b.dec_qty, 0) dec_qtyFROM    ( SELECT    a.dfeesum_no ,                    a.opr_amt ,                    a.dec_camt ,                    a.dec_comprate ,                    a.dec_ramt ,                    a.dec_qty          FROM      ctlm8686 a          UNION ALL          SELECT    a.dfeesum_no ,                    a.dec_amt ,                    a.dec_compamt ,                    a.dec_comprate ,                    a.dec_corramt ,                    a.opr_qty          FROM      dfeeapp_03 a        ) a        LEFT JOIN ( SELECT  dfeesum_no ,                            SUM(dec_ramt) dec_pay ,                            SUM(dec_corramt) dec_corrpay ,                            SUM(dec_qty) dec_qty ,                            SUM(dec_deduamt) dec_deduamt,                            SUM(dec_deduqty) dec_deduqty                    FROM   dfeepay_03                    WHERE flag_dedu = '1'                    GROUP BY dfeesum_no                  ) b ON a.dfeesum_no = b.dfeesum_no                

　　跑这个视图的查询语句，从原来的一分半钟降到一分钟，对于整个SQL而言，则从原来跑几分钟的直接10S出结果。