将一列中多行相同的值只显示在一行

数据库环境：SQL SERVER 2008R2

需求如题，左图为初始数据，右图是已实现需求的数据展示

简单说下我的实现思路

1.按id、name排序给原始数据生成行号

2.用递归判断上下行的id是否相等，第一次出现计数器初始值为1，后面再出现则计数器+1

3.对步骤2中生成的结果集再处理，计数器为1的id不变，计数器大于1则id为空字符串

我把实现的代码贴出来

/*准备基础数据*/WITH    x0          AS ( SELECT   1 AS id ,                        'a' AS NAME               UNION ALL               SELECT   1 AS id ,                        'b' AS NAME               UNION ALL               SELECT   1 AS id ,                        'c' AS NAME               UNION ALL               SELECT   2 AS id ,                        'e' AS NAME               UNION ALL               SELECT   2 AS id ,                        'd' AS NAME               UNION ALL               SELECT   3 AS id ,                        'f' AS NAME               UNION ALL               SELECT   4 AS id ,                        'h' AS NAME               UNION ALL               SELECT   4 AS id ,                        'j' AS NAME             ),/*按id、name排序生成行号*/        x1          AS ( SELECT   ROW_NUMBER() OVER ( ORDER BY id, name ) AS tid ,                        CAST(id AS VARCHAR(2)) id ,                        name               FROM     x0             ),/*递归设置计数器*/        x2 ( tid, id, name, level )          AS ( SELECT   tid ,                        id ,                        name ,                        1 AS level               FROM     x1               WHERE    tid = 1               UNION ALL               SELECT   t1.tid ,                        t1.id ,                        t1.NAME ,                        CASE WHEN t1.id = t2.id THEN level + 1                             ELSE 1                        END level               FROM     x1 t1                        INNER JOIN x2 t2 ON t1.tid = t2.tid + 1             )    /*计数器为1则id不动，否则置为空字符串*/    SELECT  CASE WHEN level = 1 THEN id                 ELSE ''            END id ,            name    FROM    x2

先比我的实现，有一网友提供了更简单的实现方式

我们来看一下他是怎么实现的

WITH    x0          AS ( SELECT   1 AS id ,                        'a' AS NAME               UNION ALL               SELECT   1 AS id ,                        'b' AS NAME               UNION ALL               SELECT   1 AS id ,                        'c' AS NAME               UNION ALL               SELECT   2 AS id ,                        'e' AS NAME               UNION ALL               SELECT   2 AS id ,                        'd' AS NAME               UNION ALL               SELECT   3 AS id ,                        'f' AS NAME               UNION ALL               SELECT   4 AS id ,                        'h' AS NAME               UNION ALL               SELECT   4 AS id ,                        'j' AS NAME               UNION ALL               SELECT   1 AS id ,                        'j' AS NAME             )    SELECT  REPLACE(CASE WHEN ROW_NUMBER() OVER ( PARTITION BY CAST(ID AS VARCHAR(2)) ORDER BY NAME ) <> '1'                         THEN 0                         ELSE CAST(ID AS VARCHAR(20))                    END, 0, '') AS ID ,            NAME    FROM    x0

实现的思路和我一样，但他的方法比我的简单，也容易理解。

我相信，实现该需求的方法不局限于这2种，欢迎各位看官提出更多的解题方法。

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